Definitions [37]
An electric charge which can be considered to exist at a single point is called a point charge.
The basic property of matter due to which it experiences electric force and shows attraction or repulsion, is called electric charge.
OR
The fundamental property of subatomic particles that gives rise to the phenomenon of experiencing force in the presence of electric and magnetic fields is called electric charge.
A unit positive charge used to test the strength of electric fields is called a test charge.
The solids which have a large number of free electrons are called conductors. (e.g. Iron, Aluminium)
The energy difference between the valence band and the conduction band is called forbidden energy gap.
The range of energies possessed by conduction electrons is called conduction band.
The range of energies possessed by valence electrons is called valence band.
The different energy levels with continuous energy variation are called energy bands.
The material with electrical conductivity between that of a conductor and an insulator, whose number of charge carriers can be controlled as per requirement, is called a semiconductor. (e.g. Silicon, Germanium)
The solids which have very small number of free electrons are called insulators. (e.g. Glass, Wood)
A field whose magnitude and direction are not the same at all points is called a non-uniform electric field.
A field whose magnitude and direction is the same at all points is called a uniform electric field.
Define electric field.
The region in which the charge experiences an electric force is the electric field around the charge.
The space surrounding an electric charge q in which another charge q0 experiences a (electrostatic) force of attraction or repulsion, is called the electric field of the charge q.
OR
Electric field due to a charge Q at a point in space may be defined as the force that a unit positive charge would experience if placed at that point.
OR
The region surrounding an electric charge or a group of charges in which another charge experiences a force is called an electric field.
A time-dependent combination of electric and magnetic fields that propagates through space and can transport energy is called an electromagnetic field.
“An electric line of force is an imaginary smooth curve drawn in an electric field along which a free, isolated positive charge moves. The tangent drawn at any point on the electric line of force gives the direction of the force acting on a positive charge placed at that point.”
OR
An imaginary curve drawn in such a way that the tangent at any given point on this curve gives the direction of the electric field is called an electric line of force.
Define Electric Flux.
A measure of electric field through a surface, given by the number of electric lines of force per unit area enclosing the electric lines of force, is called electric flux.
An electric dipole is a pair of equal and opposite point-charges placed at a short distance apart.
OR
A system formed by two equal and opposite point charges placed at a small distance apart is called an electric dipole.
“The line joining the two charges, pointing from the negative charge to the positive charge. This is known as the ‘direction of dipole axis’.”
Define electric dipole moment.
The electric dipole moment is defined as the product of the magnitude of one of the charges and the distance between the two equal and opposite charges.
When charge is distributed along a line, the charge distribution is called linear charge distribution.
When charge is distributed over a surface, the charge distribution is called surface charge distribution.
When charge is distributed over the volume of an object, it is called volume charge distribution.
The charge per unit area on a surface, is called surface charge density.
The charge per unit volume in a region of space, is called volume charge density.
OR
When charge is distributed over the volume of an object, it is called volume charge distribution.
A charge distribution in which charge is treated as continuously spread over a line, surface, or volume (ignoring microscopic discreteness), is called continuous charge distribution.
The charge per unit length along a line (such as a wire), is called linear charge density.
OR
When charge is distributed along a line, the charge distribution is called linear charge distribution.
“1 radian is the angle which an arc of length equal to the radius of a circle subtends at the centre of the circle.”
The arc of a circle subtends an angle at the centre of the circle. This angle is called a 'plane angle'.
In an electric field, the ratio of electric flux through a surface to the area A of the surface is called the 'electric flux density' at the location of the surface.
Mathematical Definition:
Electric flux density = \[\frac {Φ_E}{A}\]
For a plane surface normal to the electric field:
Electric flux density = \[\frac {E A}{A}\] = E
The electric flux linked with a surface in an electric field may be defined as the surface integral of the normal component of the electric field over that surface.
The electric flux is a measure of the number of lines of force passing through some surface held in the electric field. It is denoted by ФE.
OR
The electric flux through a surface is the dot product of the electric field and the area vector of the surface, is called electric flux.
“1 steradian is the solid angle subtended by a part of the surface of a sphere at the centre of the sphere, when the area of the part is equal to the square of the radius of the sphere.”
Conductors are those through which electric charge can easily flow. Metals, human body, earth, mercury and electrolytes are conductors of electricity.
OR
Substances which offer high resistance to the passage of electricity and do not allow electricity to pass through them easily, are called insulators.
OR
The material through which electric charge can flow easily is called a conductor.
Substances whose resistance to the movement of charges is intermediate between conductors and insulators, are called semiconductors.
Those substances in which electric charge cannot flow are called ‘insulators' (or dielectrics). Glass, hard-rubber, plastics and dry wood are insulators. Insulators have practically no free electrons.
OR
The material in which electrons are tightly bound to the nucleus and thus not available for conductance is called an insulator.
Formulae [11]
\[\vec{E}=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}\hat{r}\]
E = \[\frac {\text {Number of electric lines of force}}{\text {Area enclosing the electric lines of force}}\]
p = q × 2a
It is a vector quantity; its direction is from −q to +q.
\[\vec τ\] = \[\vec p\] × \[\vec E\]
Magnitude: τ = pE sin θ
λ = \[\frac {ΔQ}{Δl}\] C/m
where ΔQ is the charge distributed over a small length Δl of the wire.
ρ = \[\frac {ΔQ}{ΔV}\] C/m3
where ΔQ is the charge distributed over a small volume ΔV of the material.
\[\vec{E}=\frac{1}{4\pi\varepsilon_0}\sum\frac{\rho\Delta V}{r^{\prime2}}\hat{r}^{\prime}\]
σ = \[\frac {ΔQ}{ΔS}\] C/m2
where ΔQ is the charge distributed over a small surface area ΔS.
ФЕ = E A cos θ
- If the plane surface is normal to the electric field (θ = 0):
ФЕ = ЕА cos 0 = ЕА - If the plane surface is parallel to the electric field (θ = 90°):
Or = E A cos 90° = 0 - For field lines entering the plane surface normally (θ = 180°):
ФЕ = ЕА cos 180° = -EA
\[\Phi_{E}=\int_{A}\vec{\mathbf{E}}\cdot d\vec{\mathbf{A}}\]
where,
∫A = is the (surface) integral over the entire surface
ΦE = is positive when lines leave the surface, negative when they enter.
OR
Electric flux through a small area element:
dΦ = E ⋅ dS = E dS cos θ
Total electric flux through a surface:
Φ = \[\int_S\vec{E}\cdot d\vec{S}\]
E = \[\frac{1}{4\pi\varepsilon_{0}}\frac{p}{r^{3}}\]
In vector notation:
\[\overrightarrow{\mathbf{E}}=-\frac{1}{4\pi\varepsilon_{0}}\frac{\overrightarrow{\mathbf{p}}}{r^{3}}\]
Theorems and Laws [3]
State Gauss’s law on electrostatics and drive expression for the electric field due to a long straight thin uniformly charged wire (linear charge density λ) at a point lying at a distance r from the wire.
Gauss' Law states that the net electric flux through any closed surface is equal to `1/epsilon_0` times the net electric charge within that closed surface.
`oint vec" E".d vec" s" = (q_(enclosed))/epsilon_o`

In the diagram, we have taken a cylindrical gaussian surface of radius = r and length = l.
The net charge enclosed inside the gaussian surface `q_(enclosed) = lambdal`
By symmetry, we can say that the Electric field will be in radially outward direction.
According to gauss' law,
`oint vec"E".d vec"s" = q_(enclosed)/epsilon_o`
`int_1 vec"E" .d vec"s" + int_2 vec"E" .d vec"s" + int_3 vec"E". d vec"s" = (lambdal)/epsilon_o`
`int_1 vec"E". d vec"s" & int_3 vec"E". d vec"s" "are zero", "Since" vec"E" "is perpendicular to" d vec"s"`
`int_2 vec"E" . d vec"s" = (lambdal)/epsilon_o`
`"at" 2, vec"E" and d vec"s" "are in the same direction, we can write"`
`E.2pirl = (lambdal)/epsilon_o`
`E = lambda/(2piepsilon_o r)`
The flux of the net electric field through a closed surface equals the net charge enclosed by the surface divided by ε0.
Formula - Gauss's Law:
Key Points of Gauss's Law:
- Applicable to any closed surface of regular or irregular shape.
- Only the enclosed charge contributes to the electric flux.
- The electric field at a point depends on the total charge distribution, both inside and outside the Gaussian surface.
Statement
Gauss’s theorem in electrostatics states that the total electric flux through any closed surface (called a Gaussian surface) is equal to \[\frac {1}{ε_0}\] times the net charge enclosed by the surface, irrespective of the shape and size of the surface.
Mathematical Form
ΦE = \[\oint\vec{E}\cdot d\vec{A}=\frac{q_{\mathrm{enc}}}{\varepsilon_0}\]
where
- \[\vec E\] = electric field intensity
- d\[\vec{A}\] = outward normal area element
- qenc = net charge enclosed
- ε0 = permittivity of free space
Proof (Outline)
Consider a point charge +q placed inside a closed surface.
The electric field at a point on the surface is
E = \[\frac{1}{4\pi\varepsilon_0}\frac{q}{r^2}\]
The flux through a small area element dA is
dΦE = \[\vec{E}\cdot d\vec{A}=EdA\cos\theta\]
Since dAcosθ = r2dΩ,
dΦE = \[\frac{q}{4\pi\varepsilon_0}d\Omega\]
Integrating over the entire closed surface,
ΦE = \[\frac{q}{4\pi\varepsilon_0}\int d\Omega\]
But the total solid angle subtended by a closed surface is 4π,
ΦE = \[\frac {q}{ε_0}\]
Hence proved.
Key Note
Gauss’s law is most useful for symmetric charge distributions (spherical, cylindrical, planar) and is valid for all inverse-square law fields.
Key Points
- Thales (≈2500 years ago) observed that amber rubbed with wool attracts light objects like paper and straw.
- William Gilbert (1600) showed that many materials, such as glass, ebonite, and sulphur, also show this effect.
- This attractive property is produced by rubbing (friction); a material showing it is said to be electrified, and the process is called frictional electricity.
- An electrified material possesses electric charge and is therefore called a charged body.
- Electric charge is quantised (q = ±ne, e = 1.6 × 10−19 C); there are two types of charges (positive and negative), as charges repel, unlike charges attract, and the SI unit of charge is coulomb (C).
- Conductors → Eg = 0 - bands overlap, electrons flow freely.
- Semiconductors → Eg < 3 eV — small gap, conducts at room temperature.
- Insulators → Eg > 5 eV — large gap, no conduction.
- Ge = 0.72 eV, Si = 1.1 eV — both semiconductors.
- Metal conductivity decreases with temp. Semiconductor conductivity increases with temp.
- A charge creates an electric field around it, even if no other charge is present.
- The electric field does not depend on the test charge used to measure it (if the test charge is very small).
- The field of a positive charge points outward; the field of a negative charge points inward.
- The strength of the electric field decreases as the distance from the charge increases.
- At equal distances from a point charge, the electric field has the same magnitude (spherical symmetry).
- The electric field due to many charges is the force on a unit test charge at that point.
- The total electric field is the vector sum of fields due to each charge (superposition principle).
- The electric field depends on the positions of the charges and changes from point to point in space.
- An electric field describes the electrical effect of a system of charges and does not depend on the test charge used to measure it.
- It is a vector quantity defined at every point in space and can vary from point to point.
- In changing situations, electromagnetic fields travel at the speed of light and can carry energy from one place to another.
- Electric field lines originate from positive charges and terminate on negative charges (or at infinity).
- The tangent to a field line at any point gives the direction of the electric field; in a uniform field, the lines are parallel and straight.
- No two electric field lines intersect, as this would imply more than one direction of the electric field at a point.
- Electric field lines do not pass through a conductor, showing that the electric field inside a conductor is zero.
- The density of field lines indicates field strength—closer lines represent a stronger field, while wider spacing represents a weaker field; the lines are continuous and imaginary, though the field is real.
- SI unit of Electric flux = N·m²·C⁻¹ or V·m (since E = N / C = V/m).
- Dimensions of electric flux: [ΦE] = [E] [A] = [ML3T−3A−1]
- Point Charge:
Using a spherical Gaussian surface, the electric field due to a point charge is
E = \[\frac{1}{4\pi\varepsilon_0}\frac{q}{r^2}\]which directly leads to Coulomb’s law. - Infinite Line of Charge:
For a uniformly charged infinite wire with linear charge density λ,
E = \[\frac{\lambda}{2\pi\varepsilon_0r}\]The field is radial and varies inversely with distance r. - Infinite Plane Sheet of Charge:
For a sheet with surface charge density σ,
E = \[\frac{\sigma}{2\varepsilon_0}\]The field is independent of distance from the sheet. - Two Parallel Charged Sheets:
The electric field is uniform between the sheets and zero outside when the sheets carry equal and opposite charges. - Charged Conductor:
The electric field inside a conductor is zero, and just outside the surface,
E = \[\frac{\sigma}{\varepsilon_0}\]where σ is surface charge density. - Uniformly Charged Spherical Shell / Conducting Sphere:
Outside the shell: behaves like a point charge at the centre
Inside the shell: the electric field is zero - Uniformly Charged Non-conducting Sphere:
Outside: E ∝ \[\frac {1}{r^2}\]Inside: E ∝ r, increasing linearly from centre to surface
- A Gaussian surface is an imaginary closed surface used to calculate the electric flux of a vector field.
- It must be a closed surface (e.g., a sphere, cylinder, or cube); open surfaces such as discs or squares are not valid.
- The shape of the Gaussian surface should match the symmetry of the charge distribution so that the electric field is uniform or normal to the surface.
- The surface must not pass through any discrete charge, though it may pass through a continuous charge distribution.
- Electric flux through a Gaussian surface depends only on the charges enclosed, even though the electric field on the surface is due to both internal and external charges.
- Gauss’ theorem establishes a connection between the electric flux through a closed surface and the charge enclosed, and is especially useful for highly symmetric charge distributions.
- An area can be treated as a vector quantity, with both magnitude (area) and direction (the outward normal to the surface).
- A solid angle is the three-dimensional analogue of a plane angle and describes how a surface appears from a point.
- The total solid angle subtended at a point by a closed surface, irrespective of its shape, is always the same.
- The solid angle subtended by an area element depends on its orientation and position relative to the point, being maximum when the area faces the point directly.
Important Questions [77]
- Show that If We Connect the Smaller and the Outer Sphere by a Wire, the Charge Q on the Former Will Always Flow to the Latter, Independent of How Large the Charge Q Is.
- A Hollow Cylindrical Box of Length 1 M and Area of Cross-section 25 Cm2 is Placed in a Three Dimensional Coordinate System as Shown in the Figure.
- Consider a System of N Charges Q1, Q2, ... Qn with Position Vectors → R 1 , → R 2 , → R 3 , ... ... → R N Relative to Some Origin 'O'.
- A Hollow Cylindrical Box of Length 0.5 M and Area of Cross-section 25 Cm2 is Placed in a Three Dimensional Coordinate System as Shown in the Figure.
- The Figure Shows the Field Lines on a Positive Charge. is the Work Done by the Field in Moving a Small Positive Charge from Q to P Positive Or Negative? Give Reason.
- Derive an expression for the electric field E due to a dipole of length '2a' at a point distant r from the centre of the dipole on the axial line
- A Point Charge (+Q) is Kept in the Vicinity of an Uncharged Conducting Plate. Sketch the Electric Field Lines Between the Charge and the Plate?
- The magnitude of the electric field due to a point charge object at a distance of 4.0 m is 9 N/C. From the same charged object the electric field of magnitude, 16 N/C will be at a distance of ______.
- Draw the Pattern of Electric Field Lines When a Point Charge +Q is Kept Near an Uncharged Conducting Plate.
- Derive an Expression for the Electric Field Due to a Dipole of Dipole Moment → P at a Point on Its Perpendicular Bisector.
- Two bar magnets are quickly moved towards a metallic loop connected across a capacitor ‘C’ as shown in the figure. Predict the polarity of the capacitor.
- Why Do the Electrostatic Field Lines Not Form Closed Loops?
- Draw the Pattern of Electric Field Lines, When a Point Charge –Q is Kept Near an Uncharged Conducting Plate.
- Why Do the Electric Field Lines Never Cross Each Other?
- Two Charges of Magnitudes −3q and + 2q Are Located at Points (A, 0) and (4a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘5a’ with Its Centre at
- A Thin Straight Infinitely Long Conducting Wire Having Charge Density λ Is Enclosed by a Cylindrical Surface of Radius R And Length L, Its Axis Coinciding with the Length of the Wire.
- Figure Shows Three Point Charges +2q, −Q and + 3q. Two Charges + 2q and −Q Are Enclosed Within a Surface ‘S’. What is the Electric Flux Due to this Configuration Through the Surface ‘S’?
- Define Electric Flux.
- Write S.I unit of electric flux.
- How Does the Electric Flux Due to a Point Charge Enclosed by a Spherical Gaussian Surface Get Affected When Its Radius is Increased?
- Find Out the Outward Flux to a Point Charge +Q Placed at the Centre of a Cube of Side ‘A’
- "The Outward Electric Flux Due to Charge +Q is Independent of the Shape and Size of the Surface Which Encloses Is."
- What is the Electric Flux Through a Cube of Side 1 Cm Which Encloses an Electric Dipole?
- Given the Electric Field in the Region E=2xi,Find the Net Electric Flux Through the Cube and the Charge Enclosed by It.
- Given a Uniform Electric Field E=5 x 10^3 i N/C , Find the Flux of this Field Through a Square of 10 cm on a Side Whose Plane is Parallel to the Y-z Plane. What Would Be the Flux Through the Same Square If the Plane Makes a 30° Angle with the X-axis ?
- Consider Two Hollow Concentric Spheres, S1 and S2, Enclosing Charges 2q and 4q Respectively as Shown in the Figure. (I) Find Out the Ratio of the Electric Flux Through Them
- The electric flux through a closed Gaussian surface depends upon ______.
- Define Electric Flux.
- Given a Uniform Electric Field → E = 2 × 10 3 ^ I N/C, Find the Flux of this Field Through a Square of Side 20 Cm, Whose Plane is Parallel to the Y−Z Plane.
- Given a Uniform Electric Filed → E = 4 × 10 3 ^ I N / C . Find the Flux of this Field Through a Square of 5 Cm on a Side Whose Plane is Parallel to the Y-z Plane.
- Two Charges of Magnitudes −2q and +Q Are Located at Points (A, 0) and (4a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘3a’ with Its Centre a
- Two Charges of Magnitudes +4q and − Q Are Located at Points (A, 0) and (− 3a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘2a’ with Its Centre
- Write the Expression for the Torque → τ Acting on a Dipole of Dipole Moment → P Placed in an Electric Field → E .
- Derive the Expression for the Electric Potential Due to an Electric Dipole at a Point on Its Axial Line.
- Depict the Orientation of the Dipole in (I) Stable, (Ii) Unstable Equilibrium in a Uniform Electric Field.
- Drive the Expression for Electric Field at a Point on the Equatorial Line of an Electric Dipole
- Find the Resultant Electric Field Due to an Electric Dipole of Dipole Moment, 2aq, (2a Being the Separation Between the Charges ±± Q) at a Point Distant 'X' on Its Equator.
- An Electric Dipole of Length 2 Cm, When Placed with Its Axis Making an Angle of 60° with a Uniform Electric Field, Experiences a Torque of 8 √ 3 Nm. Calculate the Potential Energy of the Dipole
- An Electric Dipole of Dipole Moment P Consists of Point Charges +Q and −Q Separated by a Distance 2a Apart. Deduce the Expression for the Electric Field E Due to the Dipole at a Distance X from the Centre of the Dipole on Its Axial Line in Terms of the Dipole Moment P
- Define electric dipole moment.
- Obtain the Expression for the Torque τ Experienced by an Electric Dipole of Dipole Moment P in a Uniform Electric Field, E .
- Depict the equipotential surfaces due to an electric dipole.
- In Which Orientation, a Dipole Placed in a Uniform Electric Field is in (I) Stable, (Ii) Unstable Equilibrium?
- Define Torque Acting on a Dipole of Dipole Moment → P Placed in a Uniform Electric Field → E Express It in the Vector from and Point Out the Direction Along Which It Acts.
- An electric dipole of length 1 cm, which placed with its axis making an angle of 60° with uniform electric field, experience a torque of 6 √ 3 N m . Calculate the potential energy
- An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of 4 square root of 3 Nm. Calculate the potential energy of the dipole, if it has charge ±8 nC
- Define Dipole Moment of an Electric Dipole. is It a Scalar Or a Vector?
- Define Electric Dipole Moment. is It a Scalar Or a Vector? Derive the Expression for the Electric Field of a Dipole at a Point on the Equatorial Plane of the Dipole.
- Answer the Following Question. Derive an Expression for the Electric Field at Any Point on the Equatorial Line of an Electric Dipole.
- An electric dipole of dipole moment P→ is placed in a uniform electric field E→ with its axis inclined to the field. Write an expression for the torque T→ experienced by the dipole in vector form.
- Deduce the Expression for the Torque → R Acting on a Planar Loop of Area → a Acting on a Planar Loop of Area → B . If the Loop is Free to Rotate, What Would Be Its Orientation in Stable
- An electric dipole of dipole moment 2 × 10-8 C-m in a uniform electric field experiences a maximum torque of 6 × 10-4 N-m. The magnitude of the electric field is ______.
- Derive the expression for the torque acting on an electric dipole, when it is held in a uniform electric field. identify the orientation of the dipole in the electric field, in which it attains a
- An electric dipole of length 2 cm is placed at an angle of 30° with an electric field 2 × 105 N/C. If the dipole experiences a torque of 8 × 10-3 Nm, the magnitude of either charge
- Deduce the Expression for the Torque Acting on a Dipole of Dipole Moment in the Presence of a Uniform Electric Field
- A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.
- State and Explain Gauss’S Law.
- A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in the Figure. What is the magnitude of the electric flux through the square? (Hint: Think of the
- A Charge ‘Q’ is Placed at the Centre of a Cube of Side L. What is the Electric Flux Passing Through Each Face of the Cube?
- A Thin Conducting Spherical Shell of Radius R Has Charge Q Spread Uniformly Over Its Surface. Using Gauss’S Law, Derive an Expression for an Electric Field at a Point Outside the Shell.
- Draw a graph of electric field E(r) with distance r from the centre of the shell for 0 ≤ r ≤ ∞.
- State Gauss’S Law for Magnetism. Explain Its Significance.
- Answer the Following Question. State Gauss'S Law for Magnetism. Explain Its Significance.
- State Gauss'S Law in Electrostatics. Show, with the Help of a Suitable Example Along with the Figure, that the Outward Flux Due to a Point Charge 'Q'. in Vacuum Within a Closed Surface
- State Gauss's law on electrostatics and drive expression for the electric field due to a long straight thin uniformly charged wire (linear charge density λ) at a point lying at a distance r from the
- A Small Conducting Sphere of Radius 'R' Carrying a Charge +Q Is Surrounded by a Large Concentric Conducting Shell of Radius Ron Which a Charge +Q Is Placed.
- A Point Object is Placed on the Principal Axis of a Convex Spherical Surface of Radius of Curvature R, Which Separates the Two Media of Refractive Indices N1 And N2 (N2 > N1).
- Find the electric field intensity due to a uniformly charged spherical shell at a point, inside the shell. Plot the graph of electric field with distance from the centre of the shell.
- Using Gauss'S Law in Electrostatics, Deduce an Expression for Electric Field Intensity Due to a Uniformly Charged Infinite Plane Sheet.
- Find the Electric Field Intensity Due to a Uniformly Charged Spherical Shell
- An Infinitely Large Thin Plane Sheet Has a Uniform Surface Charge Density +σ. Obtain the Expression for the Amount of Work Done in Bringing a Point Charge Q from Infinity to a Point, Distant R,
- Find the ratio of the potential differences that must be applied across the parallel and series combination of two capacitors C1 and C2 with their capacitances
- Use Gauss'S Law to Find the Electric Field Due to a Uniformly Charged Infinite Plane Sheet. What is the Direction of Field for Positive and Negative Charge Densities
- How is the Field Directed If (I) the Sheet is Positively Charged, (Ii) Negatively Charged?
- Using Gauss’S Law, Prove that the Electric Field at a Point Due to a Uniformly Charged Infinite Plane Sheet is Independent of the Distance from It.
- A thin metallic spherical shell of radius R carries a charge Q on its surface. A point charge`Q/2` is placed at its centre C and an other charge +2Q is placed outside the shell at a distance x from the centre
- Using Gauss’ Law Deduce the Expression for the Electric Field Due to a Uniformly Charged Spherical Conducting Shell of Radius R at a Point(I) Outside and (Ii) Inside the Shell.
Concepts [16]
- Electric Charge
- Electrical Conduction in Solids
- Electric Field
- Electric Field Due to a System of Charges
- Physical Significance of Electric Field
- Electric Lines of Force
- Electric Flux
- Electric Dipole
- Dipole in a Uniform External Field
- Continuous Charge Distribution
- Gauss’s Law
- Charging by Induction
- Uniformly Charged Infinite Plane Sheet and Uniformly Charged Thin Spherical Shell (Field Inside and Outside)
- Overview: Gauss' Theorem
- Conductors and Insulators
- Electric Field due to an Electric Dipole
