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Karnataka Board PUCPUC Science 2nd PUC Class 12

A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in the Figure. What is the magnitude of the electric flux through the square?

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Question

A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in the Figure. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with edge 10 cm.)

Numerical
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Solution

Based on the illustration, we can assume that the given square represents one side of a cube with an edge length of 10 cm.

The cube encloses the +10 µC charge because it is located 5 cm above the square’s center. According to Gauss’s theorem, cube-linked electric flow is:

Φ = `q/ε_0`

= `(10 xx 10^-6)/(8.85 xx 10^-12)`

= 1.13 × 106 N m2 C−1

Since the charge is at the centre, the flux is equally distributed through the 6 faces of the cube.

Therefore, flux through one square face:

Φsq = `Φ/6`

= `1.13/6 xx 10^6`

= 0.188 × 106 N m2 C−1

or Φsq = 1.9 × 105 N m2 C−1

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Chapter 1: Electric Charge and Fields - EXERCISES [Page 43]

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NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charge and Fields
EXERCISES | Q 1.17 | Page 43
NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charges and Fields
Exercise | Q 1.18 | Page 47

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