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Question
A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.
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Solution
ccording to Gauss's Law, flux passing through any closed surface is equal to `1/∈_0` tin the charge enclosed by that surface.
`=> phi = "q"/∈_0,`
where ϕ is the flux through the closed surface and q is the charge enclosed by that surface.
The charge is placed at the centre of the cube and the electric field is passing through the six surfaces of the cube.vSo, we can say that the total electric flux passes equally through these six surfaces .
Thus, flux through each surface,
`phi ′ = "Q"/(6∈_0)`
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[Given q = charge ε0 = permittivity of free space]
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