Advertisements
Advertisements
Question
Five charges q1, q2, q3, q4, and q5 are fixed at their positions as shown in figure. S is a Gaussian surface. The Gauss’s law is given by `oint_s E.ds = q/ε_0`
Which of the following statements is correct?
Options
E on the LHS of the above equation will have a contribution from q1, q5 and q3 while q on the RHS will have a contribution from q2 and q4 only.
E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only.
E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q1, q3 and q5 only.
Both E on the LHS and q on the RHS will have contributions from q2 and q4 only.
Advertisements
Solution
E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only.
Explanation:
According to Gauss’ law, the term `q_(enclosed)` on the right side of the equation `oint_s E.ds = q_(enclosed)/ε_0` includes the sum of all charges enclosed by the surface called (Gaussian surface). In left side equation, the electric field is due to all the charges present both inside as well as outside the Gaussian surface.
APPEARS IN
RELATED QUESTIONS
A charge ‘q’ is placed at the centre of a cube of side l. What is the electric flux passing through each face of the cube?
A thin conducting spherical shell of radius R has charge Q spread uniformly over its surface. Using Gauss’s law, derive an expression for an electric field at a point outside the shell.
A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.
Gaussian surface cannot pass through discrete charge because ____________.
The Gaussian surface ______.
Which of the following statements is not true about Gauss’s law?
Gauss' law helps in ______
The Electric flux through the surface
 (i) |
 (ii) |
 (iii) |
 (iv) |
Consider a region inside which there are various types of charges but the total charge is zero. At points outside the region
- the electric field is necessarily zero.
- the electric field is due to the dipole moment of the charge distribution only.
- the dominant electric field is `∞ 1/r^3`, for large r, where r is the distance from a origin in this region.
- the work done to move a charged particle along a closed path, away from the region, will be zero.
An arbitrary surface encloses a dipole. What is the electric flux through this surface?
If the total charge enclosed by a surface is zero, does it imply that the elecric field everywhere on the surface is zero? Conversely, if the electric field everywhere on a surface is zero, does it imply that net charge inside is zero.
A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.
In the diagram, the total electric flux through the closed surface ‘S’ is:
[Given q = charge ε0 = permittivity of free space]
A charge of +5 μC is placed at the centre of two concentric spheres of radii r1 = 3 cm and r2 = 5 cm. The ratio of the flux through sphere of radius r1 to that through sphere of radius r2 will be ______.
