English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Five charges q1, q2, q3, q4, and q5 are fixed at their positions as shown in figure. S is a Gaussian surface. The Gauss’s law is given by ε∮sE.ds=qε0Which of the following statements is correct? - Physics

Advertisements
Advertisements

Question

Five charges q1, q2, q3, q4, and q5 are fixed at their positions as shown in figure. S is a Gaussian surface. The Gauss’s law is given by `oint_s E.ds = q/ε_0`

Which of the following statements is correct?

Options

  • E on the LHS of the above equation will have a contribution from q1, q5 and q3 while q on the RHS will have a contribution from q2 and q4 only.

  • E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only.

  • E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q1, q3 and q5 only.

  • Both E on the LHS and q on the RHS will have contributions from q2 and q4 only.

MCQ
Advertisements

Solution

E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only.

Explanation:

According to Gauss’ law, the term `q_(enclosed)` on the right side of the equation `oint_s E.ds = q_(enclosed)/ε_0` includes the sum of all charges enclosed by the surface called (Gaussian surface). In left side equation, the electric field is due to all the charges present both inside as well as outside the Gaussian surface.

shaalaa.com
  Is there an error in this question or solution?
Chapter 1: Electric Charges And Fields - MCQ I [Page 3]

APPEARS IN

NCERT Exemplar Physics [English] Class 12
Chapter 1 Electric Charges And Fields
MCQ I | Q 1.04 | Page 3

RELATED QUESTIONS

State and explain Gauss’s law.


A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.


State Gauss’s law for magnetism. Explain its significance. 


Answer the following question.
State Gauss's law for magnetism. Explain its significance.


State Gauss’s law on electrostatics and drive expression for the electric field due to a long straight thin uniformly charged wire (linear charge density λ) at a point lying at a distance r from the wire.


Gaussian surface cannot pass through discrete charge because ____________.


Gauss’s law is true only if force due to a charge varies as ______.

The Gaussian surface ______.


The surface considered for Gauss’s law is called ______.


Gauss' law helps in ______


The Electric flux through the surface


(i)

(ii)

(iii)

(iv)

If there were only one type of charge in the universe, then ______.

  1. `oint_s` E.dS ≠ 0 on any surface.
  2. `oint_s` E.dS = 0 if the charge is outside the surface.
  3. `oint_s` E.dS could not be defined.
  4. `oint_s` E.dS = `q/ε_0` if charges of magnitude q were inside the surface.

Consider a region inside which there are various types of charges but the total charge is zero. At points outside the region

  1. the electric field is necessarily zero.
  2. the electric field is due to the dipole moment of the charge distribution only.
  3. the dominant electric field is `∞ 1/r^3`, for large r, where r is the distance from a origin in this region.
  4. the work done to move a charged particle along a closed path, away from the region, will be zero.

Refer to the arrangement of charges in figure and a Gaussian surface of radius R with Q at the centre. Then

  1. total flux through the surface of the sphere is `(-Q)/ε_0`.
  2. field on the surface of the sphere is `(-Q)/(4 piε_0 R^2)`.
  3. flux through the surface of sphere due to 5Q is zero.
  4. field on the surface of sphere due to –2Q is same everywhere.

An arbitrary surface encloses a dipole. What is the electric flux through this surface?


In 1959 Lyttleton and Bondi suggested that the expansion of the Universe could be explained if matter carried a net charge. Suppose that the Universe is made up of hydrogen atoms with a number density N, which is maintained a constant. Let the charge on the proton be: ep = – (1 + y)e where e is the electronic charge.

  1. Find the critical value of y such that expansion may start.
  2. Show that the velocity of expansion is proportional to the distance from the centre.

A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×