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प्रश्न
Five charges q1, q2, q3, q4, and q5 are fixed at their positions as shown in figure. S is a Gaussian surface. The Gauss’s law is given by `oint_s E.ds = q/ε_0`
Which of the following statements is correct?
विकल्प
E on the LHS of the above equation will have a contribution from q1, q5 and q3 while q on the RHS will have a contribution from q2 and q4 only.
E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only.
E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q1, q3 and q5 only.
Both E on the LHS and q on the RHS will have contributions from q2 and q4 only.
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उत्तर
E on the LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q2 and q4 only.
Explanation:
According to Gauss’ law, the term `q_(enclosed)` on the right side of the equation `oint_s E.ds = q_(enclosed)/ε_0` includes the sum of all charges enclosed by the surface called (Gaussian surface). In left side equation, the electric field is due to all the charges present both inside as well as outside the Gaussian surface.
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संबंधित प्रश्न
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Gaussian surface cannot pass through discrete charge because ____________.
The surface considered for Gauss’s law is called ______.
Which of the following statements is not true about Gauss’s law?
Gauss' law helps in ______
The Electric flux through the surface
 (i) |
 (ii) |
 (iii) |
 (iv) |
If there were only one type of charge in the universe, then ______.
- `oint_s` E.dS ≠ 0 on any surface.
- `oint_s` E.dS = 0 if the charge is outside the surface.
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Refer to the arrangement of charges in figure and a Gaussian surface of radius R with Q at the centre. Then
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- field on the surface of the sphere is `(-Q)/(4 piε_0 R^2)`.
- flux through the surface of sphere due to 5Q is zero.
- field on the surface of sphere due to –2Q is same everywhere.
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