हिंदी

A Thin Conducting Spherical Shell of Radius R Has Charge Q Spread Uniformly Over Its Surface. Using Gauss’S Law, Derive an Expression for an Electric Field at a Point Outside the Shell.

Advertisements
Advertisements

प्रश्न

A thin conducting spherical shell of radius R has charge Q spread uniformly over its surface. Using Gauss’s law, derive an expression for an electric field at a point outside the shell.

Advertisements

उत्तर

According to Gauss law,

`epsi_0EointdA=q`

Where,

q is the point charge

E is electric field due to the point charge

dA is a small area on the Gaussian surface at any distance and

`epsi_0` is the proportionality constant

For a spherical shell at distance r from the point charge, the integral `ointdA` is merely the sum of all differential of dA on the sphere.

Therefore, `oint dA =4pir^2`

`epsi_0E(4pir^2) = q`

or `,E = q/(epsi4pir^2)`

Therefore, for a thin conducting spherical shell of radius R and charge Q, spread uniformly over its surface, the electric field at any point outside the shell is

`E = Q/(e_0 4pir^2)`

Where r is the distance of the point from the centre of the shell.

`E = q/(4piepsi_0r^2)`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2008-2009 (March) Delhi set 1

संबंधित प्रश्न

q1, q2, q3 and q4 are point charges located at points as shown in the figure and S is a spherical gaussian surface of radius R. Which of the following is true according to the Gauss' law?


Gauss’s law is true only if force due to a charge varies as ______.

The surface considered for Gauss’s law is called ______.


Which of the following statements is not true about Gauss’s law?


The Electric flux through the surface


(i)

(ii)

(iii)

(iv)

Five charges q1, q2, q3, q4, and q5 are fixed at their positions as shown in figure. S is a Gaussian surface. The Gauss’s law is given by `oint_s E.ds = q/ε_0`

Which of the following statements is correct?


If there were only one type of charge in the universe, then ______.

  1. `oint_s` E.dS ≠ 0 on any surface.
  2. `oint_s` E.dS = 0 if the charge is outside the surface.
  3. `oint_s` E.dS could not be defined.
  4. `oint_s` E.dS = `q/ε_0` if charges of magnitude q were inside the surface.

An arbitrary surface encloses a dipole. What is the electric flux through this surface?


If the total charge enclosed by a surface is zero, does it imply that the elecric field everywhere on the surface is zero? Conversely, if the electric field everywhere on a surface is zero, does it imply that net charge inside is zero.


In 1959 Lyttleton and Bondi suggested that the expansion of the Universe could be explained if matter carried a net charge. Suppose that the Universe is made up of hydrogen atoms with a number density N, which is maintained a constant. Let the charge on the proton be: ep = – (1 + y)e where e is the electronic charge.

  1. Find the critical value of y such that expansion may start.
  2. Show that the velocity of expansion is proportional to the distance from the centre.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×