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प्रश्न
The Electric flux through the surface
![]() (i) |
![]() (ii) |
![]() (iii) |
![]() (iv) |
विकल्प
in Figure (iv) is the largest.
in Figure (iii) is the least.
in Figure (ii) is same as Figure (iii) but is smaller than Figure (iv)
is the same for all the figures.
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उत्तर
is the same for all the figures.
Explanation:
According to Gauss’ law of electrostatics, the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity,
i.e., `phi = (Q_(enclosed))/ε_0`
Thus, electric flux through a surface doesn’t depend on the shape, size or area of a surface but it depends on the amount of charge enclosed by the surface.
In the given figures the charge enclosed is the same that means the electric flux through all the surfaces should be the same.
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संबंधित प्रश्न
A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.
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If there were only one type of charge in the universe, then ______.
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Refer to the arrangement of charges in figure and a Gaussian surface of radius R with Q at the centre. Then

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- Find the critical value of y such that expansion may start.
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