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A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.

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प्रश्न

A charge Q is placed at the centre of a cube. Find the flux of the electric field through the six surfaces of the cube.

संक्षेप में उत्तर
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उत्तर

ccording to Gauss's Law, flux passing through any closed surface is equal to `1/∈_0` tin the charge enclosed by that surface.

`=> phi = "q"/∈_0,`

where ϕ is the flux through the closed surface and q is the charge enclosed by that surface.
The charge is placed at the centre of the cube and the electric field is passing through the six surfaces of the cube.vSo, we can say that the total electric flux passes equally through these six surfaces .
Thus, flux through each surface,

`phi ′ = "Q"/(6∈_0)`

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अध्याय 30: Gauss’s Law - Exercises [पृष्ठ १४१]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 30 Gauss’s Law
Exercises | Q 5 | पृष्ठ १४१

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Answer the following question.
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The Gaussian surface ______.


The Electric flux through the surface


(i)

(ii)

(iii)

(iv)

Consider a region inside which there are various types of charges but the total charge is zero. At points outside the region

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  3. the dominant electric field is `∞ 1/r^3`, for large r, where r is the distance from a origin in this region.
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