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प्रश्न
A charge ‘q’ is placed at the centre of a cube of side l. What is the electric flux passing through each face of the cube?
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उत्तर
By using Gauss’s Law.
It is given as
`Phi = oint vecE*dvecs = q/in_0`
Now, the flux passing through all the six surfaces would be
`Phi = 6phi =q/in_0`
And the flux passing through each surface would be
`phi = q/(6in_0)`
संबंधित प्रश्न
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The Electric flux through the surface
 (i) |
 (ii) |
 (iii) |
 (iv) |
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[Given q = charge ε0 = permittivity of free space]
