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Question
An arbitrary surface encloses a dipole. What is the electric flux through this surface?
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Solution
According to Gauss' law, the electric flux through an enclosed surface is given by `oint_s vecE * dvecS = q_(enclosed)/ε_0`.
The net charge on a dipole is given by –q + q = 0, hence `q_(enclosed)` = 0
Hence the electric flux through a surface enclosing a dipole = `(-q + q)/ε_0 = q/ε_0` = 0
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