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Question
An electric dipole of length 1 cm, which placed with its axis making an angle of 60° with uniform electric field, experience a torque of \[6\sqrt{3} Nm\] . Calculate the potential energy of the dipole if it has charge ±2 nC.
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Solution
Torque,
Potential energy,
\[\frac{\tau}{U} = \frac{\left( Ql \right)E\sin\theta}{- \left( Ql \right)E\cos\theta} = - \tan\theta\]
\[ \Rightarrow U = - \frac{\tau}{\tan\theta}\]
\[ \Rightarrow U = - \frac{\tau}{\tan {60}^o}\]
\[ \Rightarrow U = - \frac{6\sqrt{3}}{\sqrt{3}}\]
\[ \Rightarrow U = - 6 J\]
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