Definitions [34]
An electric charge which can be considered to exist at a single point is called a point charge.
A unit positive charge used to test the strength of electric fields is called a test charge.
The basic property of matter due to which it experiences electric force and shows attraction or repulsion, is called electric charge.
OR
The fundamental property of subatomic particles that gives rise to the phenomenon of experiencing force in the presence of electric and magnetic fields is called electric charge.
- Positive charge: Deficiency of electrons
- Negative charge: Excess of electrons
- SI unit: Coulomb (C)
- Dimension: [M0L0T1A1]
Those substances in which electric charge cannot flow are called ‘insulators' (or dielectrics). Glass, hard-rubber, plastics and dry wood are insulators. Insulators have practically no free electrons.
OR
The material in which electrons are tightly bound to the nucleus and thus not available for conductance is called an insulator.
OR
Substances which offer high resistance to the passage of electricity and do not allow electricity to pass through them easily, are called insulators.
Conductors are those through which electric charge can easily flow. Metals, human body, earth, mercury and electrolytes are conductors of electricity.
OR
The material through which electric charge can flow easily is called a conductor.
Substances whose resistance to the movement of charges is intermediate between conductors and insulators, are called semiconductors.
The ratio of the force between two point charges placed at a certain distance apart in free space or vacuum to the force between the same two point charges when placed at the same distance in the given medium is called relative permittivity (K) or dielectric constant.
The force of attraction or repulsion acting between two electric charges is called the electric force.
The electric field intensity at any point is the strength of the electric field at that point.
- It is defined as the force experienced by a unit positive charge placed at that point.
\[\vec{E}=\frac{\vec{F}}{q_0}=\frac{kq}{r^2}\hat{r}=\frac{kq}{r^3}\vec{r}\]
- The SI unit of E is NC−1 (newtons per coulomb).
The charge Q that produces the electric field is called the source charge.
The charge q that tests the effect of the source charge is called the test charge.
A field whose magnitude and direction is the same at all points is called a uniform electric field.
A field whose magnitude and direction are not the same at all points is called a non-uniform electric field.
The space surrounding an electric charge q in which another charge q0 experiences a (electrostatic) force of attraction or repulsion, is called the electric field of the charge q.
OR
Electric field due to a charge Q at a point in space may be defined as the force that a unit positive charge would experience if placed at that point.
OR
The region surrounding an electric charge or a group of charges in which another charge experiences a force is called an electric field.
Define electric field.
The region in which the charge experiences an electric force is the electric field around the charge.
A time-dependent combination of electric and magnetic fields that propagates through space and can transport energy is called an electromagnetic field.
Electric Field \[\vec E\] at a point is the electrostatic force \[\vec F\] experienced by a vanishingly small positive test charge q0 placed at that point:
\[\vec E\] = \[\frac {\vec F}{q_0}\]
| Quantity | Symbol | SI Unit |
|---|---|---|
| Electric Field | \[\vec E\] | N C⁻¹ or V m⁻¹ |
| Force | \[\vec F\] | Newton (N) |
| Test Charge | q0 | Coulomb (C) |
An electric field line is an imaginary curve (straight or curved) drawn in a region of electric field such that:
- The tangent at any point on the curve gives the direction of the electric field \[\vec E\] at that point.
- The density (closeness) of field lines at any region represents the relative magnitude of the electric field at that region.
A measure of electric field through a surface, given by the number of electric lines of force per unit area enclosing the electric lines of force, is called electric flux.
OR
Electric flux through a surface is defined as the dot product of the electric field vector and the area vector of the surface.
For any general surface,
Define Electric Flux.
An electric dipole is a pair of equal and opposite point charges placed at a short distance apart.
OR
A system formed by two equal and opposite point charges placed at a small distance apart is called an electric dipole.
OR
A system of two equal and opposite point charges +q and −q separated by a small fixed distance 2a is called an electric dipole.
- The total charge of an electric dipole is zero
- Zero net charge does not mean zero electric field - the field exists because the charges are spatially separated
- The midpoint of the line joining −q and +q is called the centre of the dipole
The midpoint of the line joining the two charges is called the centre of the dipole.
The line passing through the centre of the dipole and perpendicular to the dipole axis is called the equatorial line.
OR
The plane passing through the centre of the dipole and perpendicular to the dipole axis is called the equatorial plane; the line along which the equatorial field is evaluated is the equatorial line (perpendicular bisector).
Define electric dipole moment.
The electric dipole moment is defined as the product of the magnitude of one of the charges and the distance between the two equal and opposite charges.
Electric dipole moment \[\vec p\] is a vector quantity defined as the product of the magnitude of either charge and the separation between them.
Mathematical definition: \[\vec p\] = q × 2a
| Symbol | \[\vec p\] |
| Magnitude | p = q × 2a |
| Direction | From −q to +q (along the dipole axis) |
| SI Unit | Coulomb-metre (C·m) |
| Dimensional Formula | [M0L1T1A1] |
“The line joining the two charges, pointing from the negative charge to the positive charge. This is known as the ‘direction of dipole axis’.”
OR
The line passing through both charges +q and −q is called the dipole axis (also called the axial line or axis of the dipole).
When charge is distributed over a surface, the charge distribution is called surface charge distribution.
OR
The surface charge density σσ is the charge per unit area at any point on the surface.
When charge is distributed over the volume of an object, it is called volume charge distribution.
OR
The volume charge density ρρ is the charge per unit volume at any point inside the body.
The charge per unit area on a surface, is called surface charge density.
The charge per unit volume in a region of space, is called volume charge density.
OR
When charge is distributed over the volume of an object, it is called volume charge distribution.
When charge is distributed along a line, the charge distribution is called a linear charge distribution.
OR
The linear charge density λ is the charge per unit length at any point on the line.
The charge per unit length along a line (such as a wire), is called linear charge density.
OR
When charge is distributed along a line, the charge distribution is called linear charge distribution.
A charge distribution in which charge is treated as continuously spread over a line, surface, or volume (ignoring microscopic discreteness), is called continuous charge distribution.
A Gaussian surface is an imaginary, closed mathematical surface chosen to apply Gauss's Law conveniently.
Formulae [8]
\[\vec{E}=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}\hat{r}\]
The dimensional formula of the electric field E is:
E = \[\frac {F}{q_0}\] = \[\frac{[LMT^{-2}]}{[IT]}=[MLT^{-3}I^{-1}]\]
For a system of n point charges q1, q2, q3,…, qn, the total electric field at point P is:
E(r) = \[{\frac{1}{4\pi\varepsilon_0}\sum_{i=1}^n\frac{q_i}{r_{iP}^2}\hat{\mathbf{r}}_{iP}}\]
Symbol Reference
| Symbol | Meaning |
|---|---|
| E(r) | Resultant electric field at point P |
| qi | The i-th source charge in the system |
| riP | Distance from charge qi to point P |
| \[\hat r_i\]P | Unit vector directed from qi toward point P |
| ε0 | Permittivity of free space |
| \[\frac {1}{4πε_0}\] | Coulomb's constant ≈ 9 × 109 Nm²C⁻² |
E = \[\frac {\text {Number of electric lines of force}}{\text {Area enclosing the electric lines of force}}\]
OR
Φ = EA cos θ
where:
- Φ = electric flux
- E = magnitude of the electric field
- A = area of the surface
- θ = angle between \[\vec{E}\] and the area vector \[\vec{E}\]
SI Unit
- SI unit of electric flux = N m² C⁻¹
- Equivalent SI unit = V m
Dimensional Formula: [ML3T-3A-1]
| Expression | Formula | Condition |
|---|---|---|
| Magnitude of Torque | τ = pE sin θ | θ = angle between \[\vec p\] and \[\vec E\] |
| Vector form | \[\vec τ\] = \[\vec p\] × \[\vec E\] | Cross product |
| Maximum Torque | τmax = pE | When θ = 90° |
| Minimum Torque | τmin = 0 | When θ = 0° or 180° |
ρ = \[\frac {ΔQ}{ΔV}\] ⇒ dq = ρ dV
where ΔQ is the charge distributed over a small volume ΔV of the material.
- SI Unit: C m⁻³ (coulomb per cubic metre)
- Nature: Scalar quantity
\[\vec{E}=\frac{1}{4\pi\varepsilon_0}\sum\frac{\rho\Delta V}{r^{\prime2}}\hat{r}^{\prime}\]
λ = \[\frac {ΔQ}{Δl}\] ⇒ dq = λdl
where ΔQ is the charge distributed over a small length Δl of the wire.
- SI Unit: C m⁻¹ (coulomb per metre)
- Nature: Scalar quantity
σ = \[\frac {ΔQ}{ΔS}\] ⇒ dq = σ dS
where ΔQ is the charge distributed over a small surface area ΔS.
- SI Unit: C m⁻² (coulomb per square metre)
- Nature: Scalar quantity
Theorems and Laws [6]
The force of attraction or repulsion between two point charges at rest is directly proportional to the product of the magnitude of the charges and inversely proportional to the square of the distance between them.
Scalar Form:
Vector Form:
where q1 and q2 are charges separated by distance r, and \[\hat r_{12}\] is the unit vector from q1 to q2.
- Since force is a vector, Coulomb's Law is better expressed in vector notation.
- The vector leading from charge 1 to charge 2 is r21 = r2 − r1, and from charge 2 to charge 1 is r12 = r1 − r2 = −r21.
- The corresponding unit vectors are \[\hat r_{21}\] = \[\frac {r_{21}}{r_{21}}\] and \[\hat r_{12}\] = \[\frac {r_{12}}{r_{12}}\], with \[\hat r_{21}\] =−\[\hat r_{12}\].
- The vector form of Coulomb's Law is:
F21 = \[\frac {1}{4πε_0}\] ⋅ \[\frac {q_1q_2}{r^2_{21}}\]\[\hat r_{21}\] ...(3) - If q1 and q2 are of the same sign, F21 is along \[\hat r_{21}\], representing repulsion.
- If q1 and q2 are of opposite signs, F21 is along −\[\hat r_{21}\], representing attraction.
- Eq. (3) handles both like and unlike charges correctly within a single equation — no separate formulas are needed.
- The force F12 on q1 due to q2 is obtained by interchanging 1 and 2: F12 = −F21, confirming agreement with Newton's Third Law.
- Eq. (3) gives the force in vacuum; when charges are placed in matter, the situation becomes more complex due to the charged constituents of the medium.
- It is experimentally verified that the force on any charge due to a number of other charges is the vector sum of all the forces on that charge, taken one at a time.
- The individual forces are unaffected by the presence of other charges.
- This is termed the Principle of Superposition.
Mathematical Formulation:
- Consider a system of three charges q1, q2, and q3.
- The force on q1 due to q2 and q3 is obtained by performing a vector addition of the forces due to each one of these charges.
- The force on q1 due to q2, denoted F12, is given by Coulomb's law even though other charges are present:
F12 = \[\frac{1}{4\pi\varepsilon_0}\cdot\frac{q_1q_2}{r_{12}^2}\hat{\mathbf{r}}_{12}\] - The force on q1 due to q3, denoted F13, is again the Coulomb force even though q2 is present:
F13 = \[\frac {1}{4πε_0}\] ⋅ \[\frac{q_1q_3}{r_{13}^2}\hat{\mathbf{r}}_{13}\] - The total force F1 on q1 due to both q2 and q3 is (Equation 1.4):
F1 = F12 + F13 = \[\frac {1}{4πε_0}\]\[\begin{bmatrix} \frac{q_1q_2}{r_{12}^2}\hat{\mathbf{r}}_{12}+\frac{q_1q_3}{r_{13}^2}\hat{\mathbf{r}}_{13} \end{bmatrix}\] - For a system of n charges, the force on q1 due to all other charges is (Equation 1.5):
F1 = \[\frac{q_{1}}{4\pi\varepsilon_{0}}\sum_{i=2}^{n}\frac{q_{i}}{r_{1i}^{2}}\hat{\mathbf{r}}_{1i}\] - The vector sum is obtained by the parallelogram law of addition of vectors.
- All of electrostatics is basically a consequence of Coulomb's law and the superposition principle.
"The electric field at any point due to a group of charges is the vector sum of the electric fields at that point due to each individual charge, calculated as if the other charges were not present."
- Each charge in the system contributes its own independent electric field at the point of interest.
- These individual fields are then added vectorially to give the total (resultant) field.
State Gauss’s law on electrostatics and drive expression for the electric field due to a long straight thin uniformly charged wire (linear charge density λ) at a point lying at a distance r from the wire.
Gauss' Law states that the net electric flux through any closed surface is equal to `1/epsilon_0` times the net electric charge within that closed surface.
`oint vec" E".d vec" s" = (q_(enclosed))/epsilon_o`

In the diagram, we have taken a cylindrical gaussian surface of radius = r and length = l.
The net charge enclosed inside the gaussian surface `q_(enclosed) = lambdal`
By symmetry, we can say that the Electric field will be in radially outward direction.
According to gauss' law,
`oint vec"E".d vec"s" = q_(enclosed)/epsilon_o`
`int_1 vec"E" .d vec"s" + int_2 vec"E" .d vec"s" + int_3 vec"E". d vec"s" = (lambdal)/epsilon_o`
`int_1 vec"E". d vec"s" & int_3 vec"E". d vec"s" "are zero", "Since" vec"E" "is perpendicular to" d vec"s"`
`int_2 vec"E" . d vec"s" = (lambdal)/epsilon_o`
`"at" 2, vec"E" and d vec"s" "are in the same direction, we can write"`
`E.2pirl = (lambdal)/epsilon_o`
`E = lambda/(2piepsilon_o r)`
"The total electric flux through any closed surface is equal to \[\frac {1}{ε_0}\] times the net charge enclosed by that surface."
Three Forms of the Law
1. Verbal Form:
The net outward electric flux through a closed surface equals the net enclosed charge divided by ε₀.
2. Algebraic Form:
ΦE = \[\frac {Q_enc}{ε_0}\]
3. Integral Form:
\[\oint\vec{E}\cdot d\vec{S}=\frac{Q_{\mathrm{enc}}}{\varepsilon_0}\]
Variable Legend
| Symbol | Meaning | SI Unit |
|---|---|---|
| ∮ | Closed surface integral | — |
| E | Electric field at the surface | N C⁻¹ |
| dS | Area element vector (outward normal) | m² |
| Qenc | Net charge enclosed by the surface | Coulomb (C) |
| ε0 | Permittivity of free space = 8.85 × 10⁻¹² C² N⁻¹ m⁻² | C² N⁻¹ m⁻² |
Key Points
- Electric charge is additive — the total charge of a system is the algebraic sum of all charges in it.
- Example: A system with +5 C and −2 C has a net charge of +3 C.
- Electrostatic forces between two point charges obey Newton's Third Law — action and reaction are equal and opposite.
- A charge creates an electric field around it, and the field exists even if the charge is removed because the space has already been modified.
- The electric field exists at every point in three-dimensional space and does not depend on the test charge used to measure it (if the test charge is very small).
- For a positive source charge, the electric field is directed radially outward, while for a negative source charge, it is directed radially inward.
- The strength of the electric field decreases as the distance from the charge increases, and at equal distances from a point charge, the field has the same magnitude.
- The force on a charge in an electric field is given by \[\vec F\](r) = q\[\vec E\](r), and the SI unit of electric field is N/C.
- The resultant field E is the vector sum of all individual fields.
- Each individual field Ei is calculated independently, as if no other charges exist.
- The unit vector \[\hat r_i\]P points from each charge qi toward point P.
- The principle holds for any number of charges in any configuration.
- This is a direct application of the Superposition Principle to electric fields.
- \[\vec E\] = \[\vec F\]/q0 — force per unit positive test charge
- Static case → Coulomb's Law is sufficient; field is a descriptive tool
- Accelerated charges → field becomes a real physical entity (EM waves)
- Time delay = d/c — information travels at the speed of light, not instantaneously
- An electric field carries and transports energy
- Field exists independently of whether any test charge is present
- Gravity is negligible for charged particles in typical electric fields
- Applicable to any closed surface, regardless of shape or size — sphere, cube, irregular shape
- Only enclosed charges contribute to the net flux; external charges do not
- The electric field E at the Gaussian surface is due to all charges (inside and outside), but the net flux depends only on enclosed charge
- Gauss's Law is valid for both stationary and moving charges
- It is one of Maxwell's four equations of electromagnetism
- Gauss's Law can be derived from Coulomb's Law for static charges, and vice versa — both are equivalent
- If net enclosed charge = 0, net flux = 0 (but E ≠ 0 necessarily)
Important Questions [55]
- Consider a System of N Charges Q1, Q2, ... Qn with Position Vectors → R 1 , → R 2 , → R 3 , ... ... → R N Relative to Some Origin 'O'.
- A Hollow Cylindrical Box of Length 1 M and Area of Cross-section 25 Cm2 is Placed in a Three Dimensional Coordinate System as Shown in the Figure.
- A Hollow Cylindrical Box of Length 0.5 M and Area of Cross-section 25 Cm2 is Placed in a Three Dimensional Coordinate System as Shown in the Figure.
- Show that If We Connect the Smaller and the Outer Sphere by a Wire, the Charge Q on the Former Will Always Flow to the Latter, Independent of How Large the Charge Q Is.
- How Does the Electric Flux Due to a Point Charge Enclosed by a Spherical Gaussian Surface Get Affected When Its Radius is Increased?
- Given a Uniform Electric Filed → E = 4 × 10 3 ^ I N / C . Find the Flux of this Field Through a Square of 5 Cm on a Side Whose Plane is Parallel to the Y-z Plane.
- Two Charges of Magnitudes −2q and +Q Are Located at Points (A, 0) and (4a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘3a’ with Its Centre a
- Consider Two Hollow Concentric Spheres, S1 and S2, Enclosing Charges 2q and 4q Respectively as Shown in the Figure. (I) Find Out the Ratio of the Electric Flux Through Them
- Two Charges of Magnitudes −3q and + 2q Are Located at Points (A, 0) and (4a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘5a’ with Its Centre at
- Two Charges of Magnitudes +4q and − Q Are Located at Points (A, 0) and (− 3a, 0) Respectively. What is the Electric Flux Due to These Charges Through a Sphere of Radius ‘2a’ with Its Centre
- A Thin Straight Infinitely Long Conducting Wire Having Charge Density λ Is Enclosed by a Cylindrical Surface of Radius R And Length L, Its Axis Coinciding with the Length of the Wire.
- The electric flux through a closed Gaussian surface depends upon ______.
- Find Out the Outward Flux to a Point Charge +Q Placed at the Centre of a Cube of Side ‘A’
- "The Outward Electric Flux Due to Charge +Q is Independent of the Shape and Size of the Surface Which Encloses Is."
- What is the Electric Flux Through a Cube of Side 1 Cm Which Encloses an Electric Dipole?
- Define Electric Flux.
- Define Electric Flux.
- Given the Electric Field in the Region E=2xi,Find the Net Electric Flux Through the Cube and the Charge Enclosed by It.
- Given a Uniform Electric Field E=5 x 10^3 i N/C , Find the Flux of this Field Through a Square of 10 cm on a Side Whose Plane is Parallel to the Y-z Plane. What Would Be the Flux Through the Same Square If the Plane Makes a 30° Angle with the X-axis ?
- Write S.I unit of electric flux.
- Figure Shows Three Point Charges +2q, −Q and + 3q. Two Charges + 2q and −Q Are Enclosed Within a Surface ‘S’. What is the Electric Flux Due to this Configuration Through the Surface ‘S’?
- Given a Uniform Electric Field → E = 2 × 10 3 ^ I N/C, Find the Flux of this Field Through a Square of Side 20 Cm, Whose Plane is Parallel to the Y−Z Plane.
- An electric dipole of length 1 cm, which placed with its axis making an angle of 60° with uniform electric field, experience a torque of 6 √ 3 N m . Calculate the potential energy
- An Electric Dipole of Dipole Moment P Consists of Point Charges +Q and −Q Separated by a Distance 2a Apart. Deduce the Expression for the Electric Field E Due to the Dipole at a Distance X from the Centre of the Dipole on Its Axial Line in Terms of the Dipole Moment P
- An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of 4 square root of 3 Nm. Calculate the potential energy of the dipole, if it has charge ±8 nC
- Drive the Expression for Electric Field at a Point on the Equatorial Line of an Electric Dipole
- Depict the Orientation of the Dipole in (I) Stable, (Ii) Unstable Equilibrium in a Uniform Electric Field.
- Derive the Expression for the Electric Potential Due to an Electric Dipole at a Point on Its Axial Line.
- Depict the equipotential surfaces due to an electric dipole.
- Obtain the Expression for the Torque τ Experienced by an Electric Dipole of Dipole Moment P in a Uniform Electric Field, E .
- Define Torque Acting on a Dipole of Dipole Moment → P Placed in a Uniform Electric Field → E Express It in the Vector from and Point Out the Direction Along Which It Acts.
- Write the Expression for the Torque → τ Acting on a Dipole of Dipole Moment → P Placed in an Electric Field → E .
- Find the Resultant Electric Field Due to an Electric Dipole of Dipole Moment, 2aq, (2a Being the Separation Between the Charges ±± Q) at a Point Distant 'X' on Its Equator.
- An Electric Dipole of Length 2 Cm, When Placed with Its Axis Making an Angle of 60° with a Uniform Electric Field, Experiences a Torque of 8 √ 3 Nm. Calculate the Potential Energy of the Dipole
- Define Electric Dipole Moment. is It a Scalar Or a Vector? Derive the Expression for the Electric Field of a Dipole at a Point on the Equatorial Plane of the Dipole.
- Define Dipole Moment of an Electric Dipole. is It a Scalar Or a Vector?
- Define electric dipole moment.
- In Which Orientation, a Dipole Placed in a Uniform Electric Field is in (I) Stable, (Ii) Unstable Equilibrium?
- Answer the Following Question. Derive an Expression for the Electric Field at Any Point on the Equatorial Line of an Electric Dipole.
- Deduce the Expression for the Torque Acting on a Dipole of Dipole Moment in the Presence of a Uniform Electric Field
- An electric dipole of length 2 cm is placed at an angle of 30° with an electric field 2 × 105 N/C. If the dipole experiences a torque of 8 × 10-3 Nm, the magnitude of either charge
- An electric dipole of dipole moment P→ is placed in a uniform electric field E→ with its axis inclined to the field. Write an expression for the torque T→ experienced by the dipole in vector form.
- Deduce the Expression for the Torque → R Acting on a Planar Loop of Area → a Acting on a Planar Loop of Area → B . If the Loop is Free to Rotate, What Would Be Its Orientation in Stable
- Derive the expression for the torque acting on an electric dipole, when it is held in a uniform electric field. identify the orientation of the dipole in the electric field, in which it attains a
- An electric dipole of dipole moment 2 × 10-8 C-m in a uniform electric field experiences a maximum torque of 6 × 10-4 N-m. The magnitude of the electric field is ______.
- A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.
- Answer the Following Question. State Gauss'S Law for Magnetism. Explain Its Significance.
- State Gauss's law on electrostatics and drive expression for the electric field due to a long straight thin uniformly charged wire (linear charge density λ) at a point lying at a distance r from the
- State Gauss'S Law in Electrostatics. Show, with the Help of a Suitable Example Along with the Figure, that the Outward Flux Due to a Point Charge 'Q'. in Vacuum Within a Closed Surface
- State and Explain Gauss’S Law.
- A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in the Figure. What is the magnitude of the electric flux through the square?
- A Thin Conducting Spherical Shell of Radius R Has Charge Q Spread Uniformly Over Its Surface. Using Gauss’S Law, Derive an Expression for an Electric Field at a Point Outside the Shell.
- Draw a graph of electric field E(r) with distance r from the centre of the shell for 0 ≤ r ≤ ∞.
- A Charge ‘Q’ is Placed at the Centre of a Cube of Side L. What is the Electric Flux Passing Through Each Face of the Cube?
- State Gauss’S Law for Magnetism. Explain Its Significance.
Concepts [15]
- Electric Charge
- Conductors and Insulators
- Basic Properties of Electric Charge
- Coulomb’s Law
- Forces between Multiple Charges
- Electric Field
- Electric Field Due to a System of Charges
- Physical Significance of Electric Field
- Electric Field Lines
- Electric Flux
- Electric Dipole
- Dipole in a Uniform External Field
- Continuous Charge Distribution
- Gauss’s Law
- Application of Gauss' Law
