Advertisements
Advertisements
Question
Consider a system of n charges q1, q2, ... qn with position vectors `vecr_1,vecr_2,vecr_3,...... vecr_n`relative to some origin 'O'. Deduce the expression for the net electric field`vec E` at a point P with position vector `vecr_p,`due to this system of charges.
Advertisements
Solution
Let us consider a system of n charges q1, q2, ... qn with position vectors r1, r2, r3, ...rn relative to origin O.

Let `vecF_i` be the force due to ith charge qi on q0.
Then,
`vecF_i = 1/(4πε_0) (q_1q_0)/(r_i^2) \ hat r_i`
Here, ri is the distance of the test charge q0 from qi.
The electric field at the observation point P is given by `vecE_i = lim_(q0->0) vecF_i/(q_0) = lim _(q0->0) 1/q_0 (1/(4πε_0) (q_1q_0)/r_1^2 hatr_i)`
`vecE_i = 1/(4πε_0) q_i/(r_1^2)hat r_i ........ (1) `
If `vecE` is the electric field at point P due to the system of charges, then by the principle of superposition of electric fields,
`vecE = vecE_1 +vecE_2 +vecE_3 +....vecE_n = sum_(i=1)^n vecE_i`
Using (1), we get
`vecE = sum_(i=1)^n 1/(4πε_0)q_i/(r_i^2)hat r_i `
`vecE =1/(4πε_0) sum_(i=1)^n q_i/(r_i^2)hat r_i`
APPEARS IN
RELATED QUESTIONS
Show that if we connect the smaller and the outer sphere by a wire, the charge q on the former will always flow to the latter, independent of how large the charge Q is.
A hollow cylindrical box of length 1 m and area of cross-section 25 cm2 is placed in a three dimensional coordinate system as shown in the figure. The electric field in the region is given by `vecE = 50xhati` where E is NC−1 and x is in metres. Find
(i) Net flux through the cylinder.
(ii) Charge enclosed by the cylinder.

The charge on a proton is +1.6 × 10−19 C and that on an electron is −1.6 × 10−19 C. Does it mean that the electron has 3.2 × 10−19 C less charge than the proton?
When the separation between two charges is increased, the electric potential energy of the charges
If a body is charged by rubbing it, its weight
Electric potential decreases uniformly from 120 V to 80 V, as one moves on the x-axis from x = −1 cm to x = +1 cm. The electric field at the origin
(a) must be equal to 20 Vcm−1
(b) may be equal to 20 Vcm−1
(c) may be greater than 20 Vcm−1
(d) may be less than 20 Vcm−1
The electric field in a region is directed outward and is proportional to the distance rfrom the origin. Taking the electric potential at the origin to be zero,
An electric field \[\vec{E} = ( \vec{i} 20 + \vec{j} 30) {NC}^{- 1}\] exists in space. If the potential at the origin is taken to be zero, find the potential at (2 m, 2 m).
Which of the following methods can be used to charge a metal sphere positively without touching it? Select the most appropriate.
