Definitions [41]
A continuous and closed path of an electric current is called an electric circuit.
Define the following:
Super conductors
Substances whose resistance decreases tremendously with decreasing temperature and reaches nearly zero near absolute zero are called superconductors; e.g., lead, tin, etc.
Define the following:
Semiconductors
Semiconductors: Substances whose resistance decreases with the increase in temperature are named as semiconductors. E.g. manganin, constantan etc.
Define an electric current.
An electric current is measured by the amount of electric charge moving per unit time at any point in the circuit.
The magnitude of an electric current is the number of electric charges flowing through a conductor in one second.
Define the following:
Electromotive force
Electromotive force: When no current is drawn from a cell, when the cell is in open circuit, the potential difference between the terminals of the cell is called its electromotive force (or e.m.f.).
Define the following:
Conventional current
The movement of the positive charge is called conventional current.
Define the unit of current.
The unit of electric current is ampere (A). When 1 C of charge flows through a conductor in 1 s, it called 1 ampere (A) current.
I = `Q/t`
Define the term resistivity.
The resistivity of a material is the resistance of a wire of that material of unit length and unit area of cross-section.
Current is defined as the rate of flow of charge.
The reciprocal of resistance is called conductllnce. It is denoted by the letter G.
Define the following:
Coulomb
One coulomb is the amount of electric charge transferred by a current of one ampere in one second.
One ohm is the resistance of a component when the potential difference of one volt applied across the component drives a current of one ampere through it.
Define temperature coefficient of resistance.
The temperature coefficient is defined as the ratio of the increase in resistivity per degree rise in temperature to its resistivity at T0.
Define Current density.
Current density is a vector quantity, often known as an area vector or cross-sectional area vector, whose value is equal to the electric current flowing per unit area.
J = `"I"/"A"`
S.I unit is A/m2.
In an electrical circuit, electric power is defined as the rate at which electrical energy is supplied by the source.
Define Electric power.
Electric power (P) is the rate at which electrical energy is transferred or consumed in an electrical circuit.
Define internal resistance of a cell.
Internal Resistance is the resistance which is present within the battery that resists the current flow when connected to a circuit.
Define potential gradient of the potentiometer wire.
The potential gradient of a potentiometer wire is defined as the change in electric potential (voltage) per unit length of the wire.
Mathematically,
Potential Gradient = `V/L`
Define a Potentiometer.
A potentiometer is a manually adjustable, variable resistor with three terminals. Two terminals are connected to the ends of a resistive element, and the third terminal is connected to an adjustable wiper. The position of the wiper sets the resistive divider ratio.
The reciprocal of specific resistance is known as conductivity.
Specific resistance of a material is the resistance of a wire of that material of unit length and unit area of cross section.
The charge flowing per second in an electric circuit is the measure of electric current in that circuit.
Mathematically,
I = \[\frac {Q}{t}\]
- 1 ampere = 1 coulomb/second ⇒ 1A = 1Cs-1
- 1 ampere = 6.25 x 1018 electrons per second
The average distance moved by a free electron between two successive collisions is called 'mean free path' of the electron.
The average time-interval between two successive collisions is called the 'relaxation time' of the electron.
If a small change ΔV in the potential difference across a part of a non-ohmic circuit causes a change ΔI in electric current, then the ratio ΔV/ΔI is called the 'dynamic resistance' of that part of the circuit.
Mathematically.
\[\frac {ΔV}{ΔI}\]
The ratio of the intensity of the electric field E at any point within the conductor and the current-density j at that point is called ‘specific resistance' or ‘electrical resistivity' of the conductor and is represented by ρ.
Mathematically,
ρ = \[\frac {E}{j}\]
Dimensions = [M L3 T-3 A-2]
The reciprocal of specific resistance is called 'specific conductance' and is represented by σ.
σ = \[\frac {1}{ρ}\]
SI unit = (ohm-metre)-1 ⇒ (Ω-m)-1
Dimension = [M-1 L-3 T3 A2]
Current density is defined as the current flowing through unit cross-sectional area drawn through that point perpendicular to the direction of flow of current.
Mathematically,
j = \[\frac {I}{A}\]
SI unit = ampere/metre2 (A m-2), Dimensions = [A L-2].
Drift velocity defined as the average velocity with which the free electrons get drifted towards the positive end of the conductor under the influence of external applied electric field.
OR
The average velocity with which free electrons drift opposite to the direction of the applied electric field.
The rate at which electric energy is transferred into other forms of energy is called ‘electric power’ P.
When two or more resistances connected between two points are replaced by a single resistance such that there is no change in the current of the circuit and the potential difference between those two points, the single resistance is called the equivalent resistance.
1 kilowatt-hour, or 1 unit, is the quantity of electric-energy which is dissipated in 1 hour in a circuit when the electric power in the circuit is 1 kilowatt.
The ratio of the potential difference to the current is called the ‘electric resistance’ R of the conductor.
Mathematically.
R = \[\frac {V}{I}\]
1 ohm = 1 volt/ampere ⇒ 1Ω = 1VA-1
Dimensions = [M L2 T-3A-2]
The mobility of a free electron is numerically equal to the magnitude of drift velocity imparted by a uniform electric field of strength 1 V-m-1.
SI unit: m2v-1s-1.
OR
The mobility m defined as the magnitude of the drift velocity per unit electric field:
μ = \[\frac {v_d}{E}\] = \[\frac {eτ}{m}\]
The potential difference between two points in an electric circuit is defined as the work done in carrying a unit charge from one point to the other.
It is an important instrument for measuring the emf of a cell or the potential difference between two points of an electric circuit.
An electric cell is a source of electrical energy which maintains a continuous flow of charge in a circuit.
The work done by the cell in forcing a unit positive charge to flow in the whole circuit (including the cell) is called the ‘electromotive force' (emf) of the cell.
Mathematically,
E = \[\frac {dW}{dq}\]
OR
The potential difference between the positive and negative terminals of a cell in an open circuit (when no current flows).
Metre bridge is a sensitive device based on the principle of Wheatstone's bridge, for the determination of the resistance of a conductor (wire).
If in the flow of 1 C of charge in a circuit, the work done by the cell be 1 J, then the emf of the cell is 1 V.
The terminal potential difference of a cell is equal to the work done for the flow of a unit charge in the external circuit only.
Mathematically,
V = \[\frac {W_{ext}}{q}\]
Formulae [8]
Electric Power P = \[\frac {W}{t}\] = VI = \[\frac {V^2}{R}\] = I2R
1 kW-h = 3.6 x 106 W-s = 3.6 × 106 J
Units = \[\frac {watt × hour}{1000}\]
vd = \[-\frac{e\mathbf{E}}{m}\tau\]
P = \[\frac {W}{t}|] = V I
Power in a Resistor:
P = I2R and P = \[\frac {V^2}{R}\]
I = \[\frac{nE}{nr+R}\]
\[\frac{1}{r_{eq}}=\frac{1}{r_1}+\frac{1}{r_2}+\ldots\]
I = \[\frac{E}{\left(\frac{r}{n}+R\right)}=\frac{nE}{r+nR}\]
r = R\[\left[\frac{E}{V}-1\right]\]
Cells in Series:
req = r1 + r2 + …
I = \[\frac{mnE}{nr+mR}\]
Theorems and Laws [7]
According to Ohm’s law, the current flowing in a conductor is directly proportional to the potential difference across its ends, provided the physical conditions and temperature of the conductor remain constant.
No, it is not always true. E.g., Diode valve, junction diode, etc., do not obey Ohm’s law.
Statement: Ohm’s Law
"The electric current flowing through a conductor is directly proportional to the potential difference across its ends, provided the temperature and other physical conditions of the conductor remain constant."
Mathematically,
I ∝ V or V = I R
where:
- V = Potential difference (in volts)
- I = Current (in amperes)
- R = Resistance of the conductor (in ohms, Ω)
Explanation:
When two conductors at different electric potentials are joined by a metallic wire, electrons flow from the conductor at a lower potential (excess electrons) to the one at a higher potential (deficit of electrons). This movement of electrons results in an electric current.
- The current continues to flow until both conductors reach the same potential.
- For continuous current flow, a constant potential difference must be maintained across the ends of the conductor (e.g., using a battery or power supply).
Derivation / Mathematical Proof:
From Ohm’s Law:
I ∝ V ⇒ \[\frac {V}{I}\] = constant
This constant is defined as the resistance (R) of the conductor. Therefore,
V = I R ---(1)
This is the mathematical form of Ohm’s Law.
Special Case:
If the current I = 1 A, then:
V = R
This implies that the resistance of a conductor is numerically equal to the potential difference across it when 1 ampere of current flows through it.
Conclusion:
Ohm's Law provides a fundamental relationship between voltage, current, and resistance in an electric circuit. It is widely used in the design and analysis of electrical and electronic systems.
Obtain the balancing condition for the Wheatstone bridge arrangements as shown in Figure 4 below:

Let `I_3` and `I_4` be the currents in resistors Q and S respectively . Let `I_g` be the current through galvanometer. For balanced condition,
`I_g = 0`
Applying junction law at ‘b’ we get
`I_1 = I_3 + I_g`
`because I_g = 0 , I_1 = I_3` ....(i)
Applying junction law at ‘d’, we get
`I_2 + I_g = I_4`
`because I_g = 0 , I_2 = I_4` ....(ii)
Applying loop law in the loop abda, we get
`-I_1·P - I_g·Q + -I_2·R = 0`
⇒ `-I_1P + I_2R = 0` (`because I_g = 0`)
⇒ `I_1P = I_2R`
⇒ `P/R = I_2/I_1` ....(iii)
Applying loop law in the loop bcdb, we get
`-I_3·Q + I_4·S + I_g·6 = 0`
⇒ `-I_3·Q + I_4·S + 0 = 0 (because I_g =0)`
⇒ `-I_3Q = I_4S`
⇒ `Q/S = I_4/I_3`
⇒ `Q/S = I_2/I_1` ...(iv) [using eq.(i) and (ii)]
From eq. (iii) and (iv), `P/ R = Q/s`
⇒ `P/Q = R/S`
This is the balanced condition.
Statement
The variation of current with voltage is the macroscopic form of Ohm’s law. When the situation is considered at a point, the law is known as Ohm’s law in microscopic (vector) form.
Explanation/Proof
From, V = \[\frac{m}{ne^2\tau}\frac{l}{A}I\]
or
\[\frac{V}{l}=\left(\frac{m}{ne^{2}\tau}\right)\left(\frac{I}{A}\right)\]
But,
\[\frac {V}{l}\] = E, \[\frac {m}{n e^2 τ}\] = ρ and \[\frac {I}{A}\] = j,
\[\therefore\] E = ρ j
Also, ρ = \[\frac {1}{σ}\]
Hence,
E = \[\frac {1}{σ}\]j or j = σ E
In vector notation,
\[\vec j\] = σ\[\vec E\]
Conclusion
Therefore, for an isotropic substance,
\[\vec j\] ∝ \[\vec E\]
and Ohm’s law in vector form states that the current density is directly proportional to the applied electric field strength, and the ratio of current density to electric field is a constant σ, independent of the electric field producing the current.
Statement
When a Wheatstone bridge is balanced, that is, when there is no deflection in the galvanometer, the ratio of the resistances of any two adjacent arms is equal to the ratio of the resistances of the remaining two adjacent arms, i.e.,
\[\frac {P}{Q}\] = \[\frac {R}{S}\]
Explanation/Proof
In a Wheatstone bridge, four resistances P, Q, R, and S are connected to form the four arms of a parallelogram. A galvanometer is connected across one diagonal and a cell across the other diagonal.

When the key is pressed, the current entering the junction is divided into two parts: current I1 flows through arm AB, and current I2 flows through arm AD. The resistances are adjusted such that there is no current through the galvanometer, indicating that the bridge is balanced.
Since there is no current in the diagonal BD, the same current I1 flows through arms AB and BC, and the same current I2 flows through arms AD and DC.
Applying Kirchhoff’s second law to loop ABDA,
I1P − I2R = 0 ⇒ I1P = I2R ---(i)
Applying Kirchhoff’s second law to loop BCDB,
I1Q − I2S = 0 ⇒ I1Q = I2S ---(ii)
Dividing equation (i) by equation (ii),
Statement
In an electric circuit, the 'algebraic' sum of the currents meeting at any junction in the circuit is zero, that is, ∑ I = 0.
Proof
When applying this law, currents entering the junction are taken as positive, while currents leaving the junction are taken as negative.

Consider a junction O where five conductors meet, carrying currents I1, I2, I3, I4 and I5.
Let I1 and I2 enter the junction, and I3, I4 and I5 leave the junction.
According to Kirchhoff’s first law,
∑ I = 0
That is,
I1 + I2 − I3 − I4 − I5 = 0
or,
I1 + I2 = I3 + I4 + I5
Thus, the sum of incoming currents is equal to the sum of outgoing currents.
Conclusion
Kirchhoff’s first law, also called Kirchhoff’s current law (KCL), states that when a steady current flows in a circuit, no charge accumulates at any junction. Hence, the law is a direct consequence of the principle of conservation of electric charge.
Statement
In any closed loop of a circuit, the algebraic sum of the products of current and the resistance in each part of the loop is equal to the algebraic sum of the emfs in that loop, that is,
∑ IR = ∑ E
Proof
While applying Kirchhoff’s second law, the following sign conventions are used:
- When we traverse a resistance in the direction of current, the product I R is taken as positive.
- The emf is taken as positive when we traverse from the negative to the positive electrode of the cell through the electrolyte.

Consider the circuit shown, containing two cells of emfs E1 and E2 and three resistances R1, R2, and R3. Let the currents in R1 and R2 be I1 and I2, respectively. Applying Kirchhoff’s first law at junction A, the current through R3 is I1 + I2.
The circuit has two closed loops.
For loop 1, applying Kirchhoff’s second law:
I1R1 − I2R2 = E1 − E2
For loop 2, applying Kirchhoff’s second law:
I2R2 + (I1 + I2)R3 = E2
Key Points
- Electricity is a convenient and controllable form of energy widely used in homes, industries, schools, and hospitals.
- Electric current is produced when electric charges flow through a conductor, and it flows only through a closed, continuous electric circuit.
- A switch completes or breaks the circuit; when the circuit is broken, current stops flowing, and devices like bulbs do not glow.
- Electric current is the rate of flow of charge, given by the relation I = Q / t, where Q is charge and t is time.
- In metallic wires, electrons are the charge carriers, but by convention, current flows from the positive to the negative terminal, in the opposite direction to electron flow.
- Electrical power represents the rate at which electrical energy is supplied by the source in an electric circuit.
- The S.I. unit of electrical power is a watt (W), and larger units such as kilowatt, megawatt, and gigawatt are used for measuring higher power.
- Specific resistance is a characteristic property of a substance and differs among metals, semiconductors, and insulators.
- Specific resistance depends on temperature: it increases with temperature for metals and decreases with temperature for semiconductors, while it remains nearly constant for some alloys.
- Specific resistance does not depend on the shape and size of the conductor and remains unchanged when a wire is stretched or doubled.
- Carbon resistors use colour codes to indicate resistance value; the first two bands give significant figures and the third band gives the multiplying power of 10.
- The fourth colour band indicates the resistor tolerance: gold (±5%), silver (±10%), and no band (±20%).
- The colour sequence Black to White represents digits 0 to 9, and the same colours in the third band represent multipliers 100 to 109.
- Series combination: Same current flows through all resistances, and the equivalent resistance is
R = R1 + R2 + R3 - Series property: In a series, the equivalent resistance is greater than the largest individual resistance, and the voltage divides in the ratio of resistances.
- Parallel combination: Same potential difference exists across all resistances and the equivalent resistance satisfies
- Parallel property: In parallel, the equivalent resistance is less than the smallest individual resistance, and current divides inversely with resistance.
- Practical use: Household electrical appliances are connected in parallel, so each works independently at the same voltage.
- Series combination: The net power consumed decreases; for identical bulbs,
Pconsumed = \[\frac {P}{n}\]and it is directly proportional to bulb resistance and inversely proportional to rated power. - Parallel combination: The net power consumed increases; for identical bulbs,
Pconsumed = n P
and it is inversely proportional to bulb resistance and directly proportional to rated power.
- Ohm’s law does not hold when temperature changes due to current flow, causing resistance to vary (e.g., filament bulb).
- In some materials, current starts flowing only after a minimum applied voltage, so the V–I graph is not linear.
- Devices like diodes, thermistors, and vacuum tubes are non-ohmic because their resistance is not constant
- Ohm’s law is not valid for all materials; in some devices, voltage is not proportional to current.
- In certain materials (like diodes), reversing the voltage does not produce equal current in the opposite direction.
- Some materials show non-unique V–I characteristics, meaning more than one voltage value may correspond to the same current.
- Metals: Resistivity increases with a rise in temperature due to increased electron collisions.
- Temperature coefficient: For metals, resistance varies with temperature as
Rt = R0(1 + αt),
and for most metals, α ≈ \[\frac {1}{273}\] per °C, so R ∝ T (approximately). - Alloys: The resistivity of alloys changes very little with temperature and remains relatively high.
- Semiconductors: Resistivity decreases with an increase in temperature due to an increase in charge carriers.
- Electrolytes: Resistivity decreases with a rise in temperature because ions move more freely.
- Null-deflection method: At balance, no current flows through the galvanometer, making the measurement independent of the cell's internal resistance.
- Uniform wire requirement: The potentiometer wire must have a uniform cross-section and material so that the potential drop along the wire is uniform.
- True emf measurement: The emf is measured in open circuit, ensuring the true value of the emf is obtained without energy loss in the cell.
- Sensitivity dependence: The sensitivity of a potentiometer increases as the potential gradient decreases, using a long wire and low current.
- Experimental precautions: Current should not flow for a long time to avoid heating of the wire, and touch the jockey lightly to prevent wire damage.
- Principle: The metre bridge works on the Wheatstone bridge principle, and balance is obtained at the null point where the galvanometer shows no deflection.
- Null point condition: At the null point, points B and D are at the same potential and
\[\frac {P}{Q}\] = \[\frac {R}{S}\] - Finding unknown resistance: If the wire is divided into lengths l and 100 − l, the unknown resistance is
S = R\[\frac {(100−l)}{l}\]. - Reducing errors: Errors are reduced by interchanging the known and unknown resistances and taking the mean value.
- Precautions: Keep the null point near the middle, avoid heating the wire, and press the jockey lightly without rubbing.
- Battery and the need for a combination of cells
A single cell cannot give a strong current, so two or more cells are combined to form a battery to obtain a suitable current or emf. - A series combination of cells
In a series combination, emfs and internal resistances add up. It is useful when the external resistance is much larger than the internal resistance. - Parallel combination of cells
In parallel combination, the emf remains the same as one cell, but the internal resistance decreases. It is useful when the external resistance is small. - Mixed grouping of cells
In mixed grouping, cells are connected in series and parallel to obtain both a large current and a suitable emf.
Imax = \[\frac {nE}{2R}\] - Condition for maximum current in mixed grouping
Maximum current flows when the battery's internal resistance equals the external resistance. i.e. \[\frac {nr}{m}\] = R
- Purpose of a rheostat: A rheostat is used to control the current in an electric circuit by changing resistance.
- Construction: It has a Nichrome wire wound on a china-clay cylinder with a sliding contact.
- As a current controller: When connected through A–C or B–C, moving the sliding contact changes the current in the circuit.
- As a potential divider: When connected across A and B, and the circuit is taken from A–C (or B–C), the rheostat provides a variable fraction of the applied potential difference.
- Working principle: Sliding the contact changes the wire's effective length, thereby changing its resistance.
Important Questions [128]
- Answer the Following Question. How is the Drift Velocity in a Conductor Affected with the Rise in Temperature?
- Define Current density.
- Identify the Region of Negative Resistance
- In the Circuit Shown in the Figure, Find the Total Resistance of the Circuit and the Current in the Arm Ad.
- Two Metallic Spheres a and B Kept on Insulating Stands Are in Contact with Each Other. a Positively Charged Rod P is Brought Near the Sphere a as Shown in the Figure.
- A current of 0.8 A flows in a conductor of 40 Ω for 1 minute. The heat produced in the conductor will be ______.
- A Metal Sphere is Kept on an Insulting Stands. a Negatively Charged Rod is Brought Near It, Then the Sphere is Earthed as Shown.
- A low voltage supply from which one needs high currents must have very low internal resistance. Why?
- A thin circular ring of radius r is charged uniformly so that its linear charge density becomes λ. Derive an expression for the electric field at a point P at a distance x from it along the axis of
- Define relaxation time.
- Two conductors, made of the same material have equal lengths but different cross-sectional areas A1 and A2 (A1 > A2). They are connected in parallel across a cell. Show
- Estimate the Average Drift Speed of Conduction Electrons in a Copper Wire
- A potential difference (V) is applied across a conductor of length 'L' and cross-sectional area 'A'. How will the drift velocity of electrons and the current density be affected if another identical
- Write Its (‘Mobility’ of Charge Carriers) S.I. Unit
- A Conductor of Length ‘L’ is Connected to a Dc Source of Potential ‘V’. If the Length of the Conductor is Tripled by Gradually Stretching It, Keeping ‘V’ Constant, How Will
- Define Relaxation Time of the Free Electrons Drifting in a Conductor. How is It Related to the Drift Velocity of Free Electrons? Use this Relation to Deduce the Expression for the Electri
- When Electrons Drift in a Metal from Lower to Higher Potential, Does It Mean that All the Free Electrons of the Metal Are Moving in the Same Direction?
- Explain the Term ‘Drift Velocity’ of Electrons in Conductor. Hence Obtain the Expression for the Current Through a Conductor in Terms of ‘Drift Velocity’.
- Explain how free electrons in a metal at constant temperature attain an average velocity under the action of an electric field. Hence, obtain an expression for it.
- Derive an expression for drift velocity of electrons in a conductor. Hence deduce Ohm's law.
- The potential difference applied across a given conductor is doubled. How will this affect (i) the mobility of electrons and (ii) the current density in the conductor? Justify your answers.
- Derive an expression for resistivity of a conductor in terms of the number density of charge carriers in the conductor and relaxation time.
- Obtain the Expression for the Current Flowing Through a Conductor Having Number Density of the Electron N, Area of Cross-section a in Terms of the Drift Velocity Vd .
- Consider two conducting wires A and B of the same diameter but made of different materials joined in series across a battery. The number density of electrons in A is 1.5 times that in B.
- How Does Drift Velocity of Electrons in a Metallic Conductor Vary with Increase in Temperature? Explain.
- A wire whose cross-sectional area is increasing linearly from its one end to the other, is connected across a battery of V volts. Which of the following quantities remain constant in the wire?
- On the basis of electron drift, derive an expression for resistivity of a conductor in terms of number density of free electrons and relaxation time. On what factors does resistivity
- Why Alloys like Constantan and Manganin Are Used for Making Standard Resistors?
- Define the Term Drift Velocity.
- Derive an Expression for Drift Velocity of Free Electrons in a Conductor in Terms of Relaxation Time.
- Estimate the Average Drift Speed of Conduction Electrons in a Copper Wire
- Estimate the Average Drift Speed of Conduction Electrons in a Copper Wire
- What is Its Relation with Relaxation Time?
- Plot a Graph Showing the Variation of Stopping Potential with the Frequency of Incident Radiation for Two Different Photosensitive Materials Having Work Functions W1 And W2 (W1 > W2).
- How Does the Resistivity of a Semiconductor Change with Rise of Temperature ? Explain.
- Two Wires of Equal Length, One of Copper and the Other of Manganin Have the Same Resistance. Which Wire is Thicker?
- A Heating Element is Marked 210 V, 630 W. Find the Resistance of the Element When Connected to a 210 V Dc Source.
- A Heating Element is Marked 210 V, 630 W. What is the Value of the Current Drawn by the Element When Connected to a 210 V Dc Source?
- Show Variation of Resistivity of Si with Temperature in a Graph ?
- A Variable Resistor R is Connected Across a Cell of Emf ε and Internal Resistance R as Shown in the Figure. Draw a Plot Showing the Variation of
- A conductor of 10 Ω is connected across a 6 V ideal source. The power supplied by the source to the conductor is ______.
- A Long Straight Current Carrying Wire Passes Normally Through the Centre of Circular Loop. If the Current Through the Wire Increases, Will There Be an Induced Emf in the Loop? Justify.
- The Plot of the Variation of Potential Difference Across a Combination of Three Identical Cells in Series, Versus Current is Shown Below. What is the Emf and Internal Resistance of Each Cell ?
- A Battery of Emf 12 V and Internal Resistance 2 Ω is Connected to a 4 Ω Resistor as Shown in the Figure. (A) Show that a Voltmeter When Placed Across the Cell and Across the Resistor, in Turn, Gives the Same Reading.
- Two Identical Cells of Emf 1.5 V Each Joined in Parallel, Supply Energy to an External Circuit Consisting of Two Resistances of 7 Ω Each Joined in Parallel.
- Distinguish Between Emf and Terminal Voltage of a Cell.
- A Cell of Emf 'E' and Internal Resistance 'r' is Connected Across a Variable Load Resistor R. Draw the Plots of the Terminal Voltage V Versus (I) R and (Ii) the Current I.
- A Cell of Emf 'E' and Internal Resistance 'R' is Connected Across a Variable Resistor 'R'. Plot a Graph Showing Variation of Terminal Voltage 'V' of the Cell Versus the Current 'I'.
- Nichrome and Copper Wires of Same Length and Same Radius Are Connected in Series. Current I is Passed Through Them. Which Wire Gets Heated up More? Justify Your Answer.
- Two Cells of Emfs 1.5 V and 2.0 V, Having Internal Resistances 0.2 Ω and 0.3 Ω, Respectively, Are Connected in Parallel. Calculate the Emf and Internal Resistance of the Equivalent Cell.
- A 10 V Cell of Negligible Internal Resistance is Connected in Parallel Across a Battery of Emf 200 V and Internal Resistance 38 ω as Shown in the Figure. Find the Value of Current in the Circuit.
- In a Potentiometer Arrangement for Determining the Emf of a Cell, the Balance Point of the Cell in Open Circuit is 350 Cm. When a Resistance of 9 ω is Used in the External Circuit of the Cell, the Balance Point Shifts to 300 Cm. Determine the Internal Resistance of the Cell.
- Plot a Graph Showing Variation of Voltage Vs the Current Drawn from the Cell. How Can One Get Information from this Plot About the Emf of the Cell and Its Internal Resistance?
- A Potentiometer Wire of Length 1.0 M Has a Resistance of 15 ω. It is Connected to a 5 V Battery in Series with a Resistance of 5 ω. Determine the Emf of the Primary Cell Which Gives a Balance
- A Cell of Emf ‘E’ and Internal Resistance ‘R’ Draws a Current ‘I’. Write the Relation Between Terminal Voltage ‘V’ in Terms of E, I and R ?
- Two Identical Cells, Each of Emf E, Having Negligible Internal Resistance, Are Connected in Parallel with Each Other Across an External Resistance R. What is the Current Through this Resistance?
- A Rectangular Conductor Lmno is Placed in a Uniform Magnetic Field of 0.5 T. the Field is Directed Perpendicular to the Plane of the Conductor.
- A Cell of Emf E and Internal Resistance R is Connected to Two External Resistance R1 And R2 And a Perfect Ammeter. the Current in the Circuit is Measured in Four Different Situations:
- Two cells of emf E1, E2 and internal resistance r1 and r2 respectively are connected in parallel as shown in the figure.Deduce the expressions for(i) the equivalent e.m.f of the combination
- A Cell of Emf ‘E’ and Internal Resistance ‘R’ is Connected Across a Variable Resistor ‘R’. Plot a Graph Showing the Variation of Terminal Potential ‘V’ with Resistance R. Predict from the Graph
- What is the End Error in a Meter Bridge? How is It Overcome? the Resistances in the Two Arms of the Metre Bridge Are R = ω and S Respectively. When the Resistance
- Answer the following question. A cell of emf E and internal resistance r is connected across a variable resistor R. Plot the shape of graphs showing a variation of terminal voltage V
- A conductor of length ‘l’ is rotated about one of its ends at a constant angular speed ‘ω’ in a plane perpendicular to a uniform magnetic field B. Plot graphs to show variations of the emf induced
- A cell of emf E is connected across an external resistance R. When current 'I' is drawn from the cell, the potential difference across the electrodes of the cell drops to V.
- Three cells, each of emf E but internal resistances 2r, 3r and 6r are connected in parallel across a resistor R. Obtain expressions for (i) current flowing in the circuit, and (ii) the terminal
- Two cells of emf E1 and E2 and internal resistances r1 and r2 are connected in parallel, with their terminals of the same polarity connected together. Obtain an expression for the equivalent
- A Wheel with 8 Metallic Spokes Each 50 Cm Long is Rotated with a Speed of 120 Rev/Min in a Plane Normal to the Horizontal Component of the Earth’S Magnetic Field. the Earth’S Magnetic Field at the P
- Two Bulbs Are Rated (P1, V) and (P2, V). If They Are Connected (I) in Series and (Ii) in Parallel Across a Supply V, Find the Power Dissipated in the Two Combinations in Terms of P1 and P2.
- Two Metallic Wires, P1 And P2 Of the Same Material and Same Length but Different Cross-sectional Areas, A1 And A2 Are Joined Together and Connected to a Source of Emf
- Twelve wires each having a resistance of 3 Ω are connected to form a cubical network. A battery of 10 V and negligible internal resistance is connected across the diagonally opposite
- Solve the Following Question. Using Kirchhoff’S Rules, Calculate the Current Through the 40 ω and 20 ω Resistors in the Following Circuit.
- Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/3) Ω?
- State the Two Kirchhoff’S Rules Used in Electric Networks. How Are There Rules Justified?
- State Kirchhoff'S Rules and Explain on What Basis They Are Justified.
- The current is drawn from a cell of emf E and internal resistance r connected to the network of resistors each of resistance r as shown in the figure. Obtain the expression for the current draw from the cell and the power consumed in the network.
- Use Kirchhoff'S Rules to Obtain Conditions for the Balance Condition in a Wheatstone Bridge.
- Using Kirchhoff’S Rules Determine the Value of Unknown Resistance R in the Circuit So that No Current Flows Through 4 ω Resistance. Also Find the Potential Difference Between a and D.
- Calculate the value of the resistance R in the circuit shown in the figure so that the current in the circuit is 0.2 A. What would b the potential difference between points B and E?
- Calculate the Value of the Resistance R in the Circuit Shown in the Figure So that the Current in the Circuit is 0.2 A. What Would B the Potential Difference Between Points a and B?
- In the Given Circuit, Assuming Point a to Be at Zero Potential, Use Kirchhoff’S Rules to Determine the Potential at Point B.
- Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/5) Ω?
- State Kirchhoff'S Rules for an Electric Network. Using Kirchhoff'S Rules, Obtain the Balance Condition in Terms of the Resistances of Four Arms of Wheatstone Bridge.
- Assertion (A): The given figure does not show a balanced Wheatstone bridge. Reason (R): For a balanced bridge small current should flow through the galvanometer.
- The Emf of a Cell is Always Greater than Its Terminal Voltage. Why? Give Reason.
- When 5 V Potential Difference is Applied Across a Wire of Length 0.1 m, the Drift Speed of Electrons is 2.5 X 10-4 M/S. If the Electron Density in the Wire is 8 X 10^28 m^-3, Calculate the Resistivity of the Material of the Wire.
- Describe the Working Principle of a Solar Cell. Mention Three Basic Processes Involved in the Generation of Emf.
- Why is Potentiometer Preferred Over a Voltmeter for Comparison of Emf. of Cells?
- Why Are Si and Gaas Preferred Materials for Solar Cells?
- In the Following Potentiometer Circuit, AB is a Uniform Wire of Length 1 m and Resistance 10Ω. Calculate the Potential Gradient Along the Wire and Balance Length Ao (= L).
- Define Internal Resistance of a Cell.
- Draw a Circuit Diagram to Determine Internal Resistance of a Cell in the Laboratory ?
- In the Figure a Long Uniform Potentiometer Wire Ab is Having a Constant Potential Gradient Along Its Length. . the Null Points for the Two Primary Cells of Emfs ε1 And ε2 Connected
- State the Working Principle of a Potentiometer. with the Help of the Circuit Diagram, Explain How a Potentiometer is Used to Compare the Emf'S of Two Primary Cells.
- Write Two Possible Causes for One Sided Deflection in a Potentiometer Experiment.
- On what factors does the potential gradient of the wire depend?
- Describe Briefly, with the Help of a Circuit Diagram, How a Potentiometer is Used to Determine the Internal Resistance of a Cell.
- Write Two Factors by Which Current Sensitivity of a Potentiometer Can Be Increased.
- State the Principle on Which a Potentiometer Works. How Can a Given Potentiometer Be Made More Sensitive?
- In the Given Circuit, with Steady Current, Calculate the Potential Drop Across the Capacitor and the Charge Stored in It.
- Two Students ‘X’ and ‘Y’ Perform an Experiment on Potentiometer Separately Using the Circuit Given Below:
- Write the Principle of Working of a Potentiometer. Describe Briefly, with the Help of a Circuit Diagram, How a Potentiometer is Used to Determine the Internal Resistance of a Given Cell.
- A student uses the circuit diagram of a potentiometer as shown in the figure (a) for a steady current I passing through the potentiometer wire, he gets a null point for the cell ε1. and not for ε2
- State the Principle of Working of a Potentiometer.
- In the Given Circuit in the Steady State, Obtain the Expressions for (A) the Potential Drop (B) the Charge and (C) the Energy Stored in the Capacitor, C.
- State the Underlying Principle of a Potentiometer ?
- A Potentiometer Wire of Length 1 M Has a Resistance of 5 ω. It is Connected to a 8 V Battery in Series with a Resistance of 15 ω. Determine the Emf of the Primary Cell Which Gives a Bala
- State the Principle of a Potentiometer. Define Potential Gradient. Obtain an Expression for Potential Gradient in Terms of Resistivity of the Potentiometer Wire.
- Figure Shows a Long Potentiometer Wire Ab Having a Constant Potential Gradient. the Null Points for the Two Primary Cells of Emfs ε1 And ε2 Connected in the Manner Shown Are Obtained at a
- In a Meter Bridge, the Null Point is Found at a Distance of L1 Cm from A. If Now a Resistance of X is Connected in Parallel with S, the Null Point Occurs at L2 Cm. Obtain a Formula for X in Terms
- In a Metre Bridge, the Balance Point is Found at a Distance L1 With Resistances R and S as Shown in the Figure.An Unknown Resistance X is Now Connected in Parallel to the Resistance S and the Balance Point is Found at a Distance L2. Obtain a Formula for X in Terms of L1, L2 and S.
- A Resistance of R Ω Draws Current from a Potentiometer as Shown in the Figure. the Potentiometer Has a Total Resistance Ro ω. a Voltage V is Supplied to the Potentiometer. Derive an Expression for the Voltage Across R When the Sliding Contact is in the Middle of the Potentiometer.
- Why is It Generally Preferred to Obtain the Balance Point in the Middle of the Meter Bridge Wire
- Write the Principle of Working of a Metre Bridge
- The Figure Shows Experimental Set up of a Meter Bridge. When the Two Unknown Resistances X and Y Are Inserted, the Null Point D is Obtained 40 Cm from the End A. When a Resistance of 10 ω Is Connected
- Why Are the Connections Between the Resistors in a Meter Bridge Made of Thick Copper Strips?
- Which Material is Used for the Meter Bridge Wire and Why?
- In a Meter Bridge Shown in the Figure, the Balance Point is Found to Be 40 cm from End A. If a Resistance of 10 Ω is Connected in Series with R, Balance Point is Obtained 60 cm from A. Calculate the Values of R and S.
- Using the Concept of Free Electrons in a Conductor, Derive the Expression for the Conductivity of a Wire in Terms of Number Density and Relaxation Time. Hence Obtain the Relation Between Current Density and the Applied Electric Field E.
- The ______, a property of materials C, Si, and Ge depends upon the energy gap between their conduction and valence bands.
- Show variation of resistivity of copper as a function of temperature in a graph.
- Define the Term 'Conductivity' of a Metallic Wire. Write Its Si Unit.
- Define the Term 'Electrical Conductivity' of a Metallic Wire. Write Its S.I. Unit.
- A carbon resistor is shown in the figure. Using color code, write the value of the resistance.
- Name the Junction Diode Whose I-V Characteristics Are Drawn Below:
- V-i Graph for a Metallic Wire at Two Different Temperature T1 and T2 is as Shown in the Figure. Which of the Two Temperature is Higher and Why?
- Sunita and her friends visited an exhibition . The policeman asked them to pass through a metal detector. Sunita's friends were initially scared of it. Sunita, however, explained to them the purpose
- A Charge Q is Distributed Uniformly Over a Metallic Sphere of Radius R. Obtain the Expressions for the Electric Field (E) and Electric Potential (V) at a Point
- Three Concentric Metallic Shells A, B and C Or Radii A, B and C (A < B < C) Have Surface Charge Densities + σ, −σ and + σ, Respectively as Shown in the Figure
Concepts [25]
- Electric Current
- Concept of Electric Currents in Conductors
- Ohm's Law
- Current Density
- Drift of Electrons and the Origin of Resistivity
- Limitations of Ohm’s Law
- Resistivity of Various Materials
- Temperature Dependence of Resistance
- Electrical Power
- Cells, Emf, Internal Resistance
- Cells in Series
- Kirchhoff’s Laws
- Wheatstone Bridge
- Conductivity and Conductance;
- Delta Star Transformation
- Potential Difference and Emf of a Cell
- Measurement of Internal Resistance of a Cell
- Potentiometer
- Metre Bridge: Slide-Wire Bridge
- A combination of resistors in both series and parallel
- Specific Resistance
- V-I Characteristics (Linear and Non-linear)
- Flow of Electric Charges in a Metallic Conductor
- Overview: Electric Resistance and Ohm's Law
- Overview: DC Circuits and Measurements
