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Question
A 10 V cell of negligible internal resistance is connected in parallel across a battery of emf 200 V and internal resistance 38 Ω as shown in the figure. Find the value of current in the circuit.
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Solution
Applying KVL in the loop ABCDA
10 + 38i - 200 = 0
38i = 190
`i = 190/38 = 5A`
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