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Nootan solutions for Mathematics [English] Class 9 ICSE chapter 7 - Logarithms [Latest edition]

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Nootan solutions for Mathematics [English] Class 9 ICSE chapter 7 - Logarithms - Shaalaa.com
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Solutions for Chapter 7: Logarithms

Below listed, you can find solutions for Chapter 7 of CISCE Nootan for Mathematics [English] Class 9 ICSE.


Exercise 7AExercise 7BExercise 7C
Exercise 7A [Page 140]

Nootan solutions for Mathematics [English] Class 9 ICSE 7 Logarithms Exercise 7A [Page 140]

1. (i)Page 140

Express the following in logarithmic form:

83 = 512

1. (ii)Page 140

Express the following in logarithmic form:

53 = 125

1. (iii)Page 140

Express the following in logarithmic form:

32 = 9

1. (iv)Page 140

Express the following in logarithmic form:

10–2 = 0.01

1. (v)Page 140

Express the following in logarithmic form:

`3^-3 = 1/27`

1. (vi)Page 140

Express the following in logarithmic form:

`2^-5 = 1/32`

2. (i)Page 140

Express the following in exponential form:

log5 125 = 3

2. (ii)Page 140

Express the following in exponential form:

log6 36 = 2

2. (iii)Page 140

Express the following in exponential form:

log4 256 = 4

2. (iv)Page 140

Express the following in exponential form:

log2 0.125 = –3

2. (v)Page 140

Express the following in exponential form:

`log_4  1/32 = - 5/2`

2. (vi)Page 140

Express the following in exponential form:

log10 0.0001 = –4

3. (i)Page 140

Evaluate the following:

`log_(6sqrt(2)) 72`

3. (ii)Page 140

Evaluate the following:

`log_(sqrt(3)) 27`

4. (i)Page 140

Evaluate the following by converting into exponential form:

log5 625

4. (ii)Page 140

Evaluate the following by converting into exponential form:

log2 8

4. (iii)Page 140

Evaluate the following by converting into exponential form:

log0.5 64

4. (iv)Page 140

Evaluate the following by converting into exponential form:

log5 0.04

4. (v)Page 140

Evaluate the following by converting into exponential form:

`log_(sqrt(3)) 9`

4. (vi)Page 140

Evaluate the following by converting into exponential form:

`log_3  1/3`

4. (vii)Page 140

Evaluate the following by converting into exponential form:

log9 243

4. (viii)Page 140

Evaluate the following by converting into exponential form:

log32 2

5. (i)Page 140

Solve for x:

log2 x = 3

5. (ii)Page 140

Solve for x:

`log_125 x = 1/3`

5. (iii)Page 140

Solve for x:

`log_(sqrt(2)) x = 4`

5. (iv)Page 140

Solve for x:

log3 x = –2

6. (i)Page 140

Solve for x:

logx 81 = 4

6. (ii)Page 140

Solve for x:

logx 32 = –5

6. (iii)Page 140

Solve for x:

logx 8 = 1

6. (iv)Page 140

Solve for x:

`log_x  1/2 = -1`

6. (v)Page 140

Solve for x:

`log_x 16 = 1/2`

6. (vi)Page 140

Solve for x:

log3 (x2 – 19) = 4

6. (vii)Page 140

Solve for x:

log (2x + 4) = 1

6. (viii)Page 140

Solve for x:

log x = –1

7.Page 140

If log10 x = y, express `10^(3y  -  1)` in terms of x.

8. (i)Page 140

If log10 x = a, log10 y = b, express `10^(a - 1)` in terms of x.

8. (ii)Page 140

If log10 x = a, log10 y = b, express `10^(3b - 2)` in terms of y.

8. (iii)Page 140

If log10 x = a, log10 y = b, If log10 c = 2a – b, find c in terms of x and y.

9.Page 140

If log2 x = a, log3 y = a, find `24^(2a + 1)` in terms of x and y.

10.Page 140

If log2 y = x, log3 z = x, express 12x in terms of y and z.

11.Page 140

If log2 x = a, log5 y = a, find `20^(2a  -  1)` in terms of x and y.

12.Page 140

If log x = a, log y = b, express x3y2 in terms of a and b.

Exercise 7B [Pages 146 - 147]

Nootan solutions for Mathematics [English] Class 9 ICSE 7 Logarithms Exercise 7B [Pages 146 - 147]

1. (i)Page 146

Evaluate the following:

`1/2 log 625 + log 8 - 1/4 log 16`

1. (ii)Page 146

Evaluate the following: 

`log 100 + 2 log 0.01 - 1/2 log 5^-4 + 2/3 log 8`

1. (iii)Page 146

Evaluate the following:

log 5 + 3 log 2 – 2 log 6 + 2 log 3

1. (iv)Page 146

Evaluate the following:

2 log 2 + 4 log 3 + log 5 – log 7.5 – log 2.16

2. (i)Page 146

Evaluate the following:

log16 32 – log9 27

2. (ii)Page 146

Evaluate the following:

log625 125 + log64 16

3. (i)Page 146

Express the following in terms of log 2 and log 3:

log 24

3. (ii)Page 146

Express the following in terms of log 2 and log 3:

log 72

3. (iii)Page 146

Express the following in terms of log 2 and log 3:

log 13.5

3. (iv)Page 146

Express the following in terms of log 2 and log 3:

log 180

4. (i)Page 146

Prove the following:

`2 log  15/4 + log  81/5 - 3 log  9/4 + log 100 = 3 + log 2`

4. (ii)Page 146

Prove the following:

`log  125/147 = 3 - 3 log 2 - 2 log 7 - log 3`

4. (iii)Page 146

Prove the following:

`log  35/33 - log  135/99 + log  24/7 = 3 log 2 - log 3`

4. (iv)Page 146

Prove the following:

2 log10 20 + log 5 – log 2 = 3

5. (i)Page 146

Express the following as a single logarithm:

2 log 5 + 3 log 2 – 1

5. (ii)Page 146

Express the following as a single logarithm:

2 log 3 + log 7 + 3 log 5 – 2

6. (i)Page 146

If log 2 = x and log 3 = y, express the following in terms of x and y.

log 36

6. (ii)Page 146

If log 2 = x and log 3 = y, express the following in terms of x and y.

log 250

6. (iii)Page 146

If log 2 = x and log 3 = y, express the following in terms of x and y.

log 14.4

7.Page 146

Prove that : `4^(log 9) = 3^(log 16)`.

8.Page 146

If log x = a + b and log y = a – b, express log (x2y) in terms of a and b.

9.Page 146

If log x = 3a + 2b and log y = 2a – b, express log (x3y2) in terms of a and b.

10. (i)Page 146

If `x = log  2/3, y = log  3/7, z = log  7/2`, find the value of x + y + z.

10. (ii)Page 146

If `x = log  2/3, y = log  3/7, z = log  7/2`, find the value of `2^(x  +  y  +  z)`.

11. (i)Page 146

If `x = log  3/7, y = log  10/7, z = log  10/3`, find the value of x – y + z.

11. (ii)Page 146

If `x = log  3/7, y = log  10/7, z = log  10/3`, find the value of `5^(x  -  y  +  z)`.

12. (i)Page 146

Find the value of x in the following:

log10 x = log10 2 + 2

12. (ii)Page 146

Find the value of x in the following:

log x = –2 + 3 log 2 – 5 log 3 + 2 log 72 + log 3

12. (iii)Page 146

Find the value of x in the following:

log (x + 2) + log (x – 2) = log 2 + log 3 + 1

12. (iv)Page 146

Find the value of x in the following:

log (x + 4) + log (x – 4) = 4 log 2 + log 3

12. (v)Page 146

Find the value of x in the following:

log (3x + 2) + log (3x – 2) = 1 + log 2 + log 7

12. (vi)Page 146

Find the value of x in the following:

`log_2 x + log_8 x + log_32 x = 23/15`

12. (vii)Page 146

Find the value of x in the following:

`log_3 x + log_9 x + log_81 x = 7/4`

13.Page 147

Prove that: (1 + loga b).logab x = loga x.

14.Page 147

Prove that: `(log x)^2 - (log y)^2 = log (x/y) · log (xy)`.

15.Page 147

If `log  (x + y)/2 = (log x + log y)/2`, prove that x = y.

16.Page 147

If `2 log  (x - y)/2 = log x + log y`, prove that x2 + y2 – 6xy = 0.

17.Page 147

If log (x + y) = log x + log y, prove that: `y = x/(x - 1)`.

18.Page 147

If log (x + y) = log x – log y, prove that `x = y^2/(1 - y)`.

19.Page 147

If x2 + y2 = 34 xy, prove that `log ((x + y)/6) = 1/2 (log x + log y)`.

20.Page 147

Show that: logb a · logc d = logc a · logb d.

21.Page 147

If `1/(log_a x) + 1/(log_c x) = 2/(log_b x)`, then prove that b2 = ac.

22.Page 147

Show that: `1/(log_36 12) + 1/(log_6 12) + 1/(log_8 12) = 3`

23.Page 147

If x = loga (bc), y = logb (ca), z = logc (ab) then prove that `1/(1 + x) + 1/(1 + y) + 1/(1 + z)` = 1

Exercise 7C [Pages 147 - 148]

Nootan solutions for Mathematics [English] Class 9 ICSE 7 Logarithms Exercise 7C [Pages 147 - 148]

Multiple Choice Questions Choose the correct answer from the given four options in each of the following questions:

1.Page 147

If log (2x + 5) = 2, then x is equal to ______.

  • 40

  • 42.5

  • 47.5

  • 48

2.Page 147

`log_(sqrt(2)) sqrt(8)` is equal to ______.

  • 3

  • 4

  • 16

  • 5

3.Page 147

The value of 4log 3 – 3log 4 is ______.

  • 0

  • 1

  • 3

  • 12

4.Page 147

If x = log 2, y = log 3, then log 12 is equal to ______.

  • 2x + 3y

  • 2x + y

  • 3x + 2y

  • x + 2y

5.Page 147

If logx 9 – logx 3 – logx 27 = 2, then x is equal to ______.

  • 9

  • 3

  • `1/9`

  • `1/3`

6.Page 148

If log2 x = a and log5 y = a, then `100^(3a - 1)` is equal to ______.

  • `(x^6y^6)/100`

  • `(x^3y^3)/100`

  • `(x^2y^2)/100`

  • `(xy)/100`

7.Page 148

log4 32 – log8 32 is equal to ______.

  • `1/3`

  • `1/2`

  • `7/6`

  • `5/6`

8.Page 148

3 – 5 log10 2 is equal to ______.

  • `log  225/4`

  • `log  125/4`

  • `log  75/4`

  • `log  25/4`

9.Page 148

If log (x + y) = log x + log y, then y is equal to ______.

  • `x/(x - 1)`

  • `(x + 1)/x`

  • `(x - 1)/x`

  • `x/(x + 1)`

10.Page 148

If `log((x + y)/5) = (logx + logy)/2`, then correct relation is ______.

  • x2 + y2 + 23 xy = 0

  • x2 + y2 – 23 xy = 0

  • x2 + y2 + 27 xy = 0

  • x2 + y2 + 27 xy = 0

Valid Statements Questions In the following questions, two statements (i) and (ii) are given. Choose the valid statement.

1.Page 148

(i) log (m · n) = log m + log n

(ii) 3 – 5 log10 2 = log10 125 – log10 4

  • Only (i)

  • Only (ii)

  • Both (i) and (ii)

  • Neither (i) nor (ii)

2.Page 148

(i) log 288 = 5 log 2 + 2 log 3

(ii) 3 log 2 + 2 log 3 – 1 = log 72

  • Only (i)

  • Only (ii)

  • Both (i) and (ii)

  • Neither (i) nor (ii)

3.Page 148

(i) log m – log n = log (mn)

(ii) If log10 (x + 5) + log10 (x – 5) = log 600, then x = 5

  • Only (i)

  • Only (ii)

  • Both (i) and (ii)

  • Neither (i) nor (ii)

4.Page 148

(i) 5log 4 = 4log 5

(ii) If `x = log  1/2, y = log  2/3`, z = log 3, then x + y + z = 0

  • Only (i)

  • Only (ii)

  • Both (i) and (ii)

  • Neither (i) nor (ii)

Solutions for 7: Logarithms

Exercise 7AExercise 7BExercise 7C
Nootan solutions for Mathematics [English] Class 9 ICSE chapter 7 - Logarithms - Shaalaa.com

Nootan solutions for Mathematics [English] Class 9 ICSE chapter 7 - Logarithms

Shaalaa.com has the CISCE Mathematics Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Nootan solutions for Mathematics Mathematics [English] Class 9 ICSE CISCE 7 (Logarithms) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Nootan textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 9 ICSE chapter 7 Logarithms are .

Using Nootan Mathematics [English] Class 9 ICSE solutions Logarithms exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Nootan Solutions are essential questions that can be asked in the final exam. Maximum CISCE Mathematics [English] Class 9 ICSE students prefer Nootan Textbook Solutions to score more in exams.

Get the free view of Chapter 7, Logarithms Mathematics [English] Class 9 ICSE additional questions for Mathematics Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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