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Evaluate the following: 1/2 ⁢log ⁡625 + log ⁡8 – 1/4 ⁢log ⁡16 - Mathematics

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Question

Evaluate the following:

`1/2 log 625 + log 8 - 1/4 log 16`

Evaluate
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Solution

Given: `1/2 log 625 + log 8 - 1/4 log 16`

Step-wise calculation:

1. `1/2 log 625`

= `log 625^(1/2)`

= log 25

2. `1/4 log 16`

= `log 16^(1/4)`

= log 2

3. So the expression

= log 25 + log 8 – log 2 

= log (25 × 8) – log 2 

= log 200 – log 2

= `log  200/2` 

= log 100

If log means base 10 common log, log 100 = 2.

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Chapter 7: Logarithms - Exercise 7B [Page 146]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 7 Logarithms
Exercise 7B | Q 1. (i) | Page 146
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