हिंदी

Evaluate the following: 1/2 ⁢log ⁡625 + log ⁡8 – 1/4 ⁢log ⁡16 - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`1/2 log 625 + log 8 - 1/4 log 16`

मूल्यांकन
Advertisements

उत्तर

Given: `1/2 log 625 + log 8 - 1/4 log 16`

Step-wise calculation:

1. `1/2 log 625`

= `log 625^(1/2)`

= log 25

2. `1/4 log 16`

= `log 16^(1/4)`

= log 2

3. So the expression

= log 25 + log 8 – log 2 

= log (25 × 8) – log 2 

= log 200 – log 2

= `log  200/2` 

= log 100

If log means base 10 common log, log 100 = 2.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Logarithms - Exercise 7B [पृष्ठ १४६]

APPEARS IN

नूतन Mathematics [English] Class 9 ICSE
अध्याय 7 Logarithms
Exercise 7B | Q 1. (i) | पृष्ठ १४६
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×