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Evaluate the following: log 100 + 2 log 0.01 – 1/2 log 5^–4 + 2/3 log 8 - Mathematics

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प्रश्न

Evaluate the following: 

`log 100 + 2 log 0.01 - 1/2 log 5^-4 + 2/3 log 8`

मूल्यांकन
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उत्तर

Given: `log 100 + 2 log 0.01 - 1/2 log 5^-4 + 2/3 log 8`

Step-wise calculation:

1. log 100

= log (102)

= 2

2. 2 log 0.01

= 2 × log (10–2

= 2 × (–2) 

= –4

3. `-1/2 log 5^-4`

= `(-1/2) xx (-4 log 5)` 

= 2 log 5

4. `2/3 log 8`

= `(2/3) xx log (2^3)` 

= `(2/3) xx (3 log 2)` 

= 2 log 2

5. Combine:

2 + (–4) + 2 log 5 + 2 log 2 

= –2 + 2(log 5 + log 2)

6. log 5 + log 2

= log (5 × 2) 

= log 10

= 1

So 2(log 5 + log 2)

= 2 × 1 

= 2

7. Therefore,

−2 + 2

= 0

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अध्याय 7: Logarithms - Exercise 7B [पृष्ठ १४६]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 7 Logarithms
Exercise 7B | Q 1. (ii) | पृष्ठ १४६
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