Question

If log₁₀ x = a, log₁₀ y = b, express `10^(3b - 2)` in terms of y.

Answer 1

Given: log₁₀ x = a, log₁₀ y = b

Step-wise calculation:

log₁₀ y = b

⇒ 10^b = y

`10^(3b - 2) = 10^(3b)/10^2`

`10^(3b - 2) = (10^b)^3/100`

`10^(3b - 2) = y^3/100`