Question

Solve for x:

`log_x  1/2 = -1`

Answer 1

Given: `log_x  1/2 = -1`

Step-wise calculation:

Convert to exponential form using the definition

log_ab = c ⇔ a^c = b:

`x^(-1) = 1/2` 

Solve `x^(-1) = 1/2`

⇒ `1/x = 1/2`

⇒ x = 2 

Check: base x must be positive and ≠ 1 and x = 2 satisfies this.