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(i) log 288 = 5 log 2 + 2 log 3 (ii) 3 log 2 + 2 log 3 – 1 = log 72 - Mathematics

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Question

(i) log 288 = 5 log 2 + 2 log 3

(ii) 3 log 2 + 2 log 3 – 1 = log 72

Options

  • Only (i)

  • Only (ii)

  • Both (i) and (ii)

  • Neither (i) nor (ii)

MCQ
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Solution

Only (i)

Explanation:

(i) 288 = 25 × 32 

So log 288

= log (25 × 32

= 5 log 2 + 2 log 3

(ii) 3 log 2 + 2 log 3 – 1

= log (23) + log (32) – log 10 

= `log ((2^3 xx 3^2)/10)` 

= log 7.2, not log 72.

So (ii) is false.

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Chapter 7: Logarithms - Exercise 7C [Page 148]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 7 Logarithms
Exercise 7C | Q 2. | Page 148
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