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(i) log m – log n = log (m^n) (ii) If log_10 (x + 5) + log_10 (x – 5) = log 600, then x = 5 - Mathematics

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Question

(i) log m – log n = log (mn)

(ii) If log10 (x + 5) + log10 (x – 5) = log 600, then x = 5

Options

  • Only (i)

  • Only (ii)

  • Both (i) and (ii)

  • Neither (i) nor (ii)

MCQ
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Solution

Neither (i) nor (ii)

Explanation:

(i) False - The correct law is `log m - log n = log (m/n); log (m^n)` equals n · log m, not log m – log n.

(ii) False - Combine the logs:

log10 (x + 5)(x – 5) = log10 600

⇒ x2 − 25 = 600 

⇒ x2 = 625

So x = ±25.

But the domain requires x – 5 > 0.

So x = 25 (not 5).

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Chapter 7: Logarithms - Exercise 7C [Page 148]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 7 Logarithms
Exercise 7C | Q 3. | Page 148
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