Advertisements
Chapters
2: Compound Interest
3: Expansions
4: Factorisation
5: Simultaneous Linear Equations
▶ 6: Indices/Exponents
7: Logarithms
8: Triangles
9: Mid-point Theorem
10: Pythagoras Theorem
11: Rectilinear Figures
12: Constructions of Polygons
13: Theorems on Area
14: Circles
15: Statistics
16: Mensuration
17: Trigonometric Ratios
18: Trigonometric Ratios of Some Standard Angles and Complementary Angles
Chapter 19: Co-ordinate Geometry: An Introduction
![Nootan solutions for Mathematics [English] Class 9 ICSE chapter 6 - Indices/Exponents Nootan solutions for Mathematics [English] Class 9 ICSE chapter 6 - Indices/Exponents - Shaalaa.com](/images/mathematics-english-class-9-icse_6:f26eb985e8254aa987299226050d7c71.jpg)
Advertisements
Solutions for Chapter 6: Indices/Exponents
Below listed, you can find solutions for Chapter 6 of CISCE Nootan for Mathematics [English] Class 9 ICSE.
Nootan solutions for Mathematics [English] Class 9 ICSE 6 Indices/Exponents Exercise 6A [Page 129]
Simplify the following:
a7 × a5
Simplify the following:
`a^9/a^4`
Simplify the following:
`(a^7 xx a^4)/a^3`
Simplify the following:
`(x^4 xx x^5)/(x^3 xx x^-1)`
Simplify the following:
`(3x^4y^2(2xy)^5)/((2x^3y^3)^2`
Simplify the following:
`((x^(2a + 3))^5)/((x^(a + 1))^3`
Simplify the following:
`((xy^3)^2(3x^2y)^4)/(xy)^3`
Simplify the following:
`(x^3y^4z^2)/(x^2y^-1z^3)`
Simplify the following:
`(6^(2n + 6) - 6^3 * 36^(n + 1))/(6^(n + 2))^2`
Simplify the following:
`(2^(n + 2) xx 4^(n + 1))/(2^(n + 1) xx 4^(n - 2))`
Simplify the following:
`(5^(n + 5) - 6 xx 5^(n + 3))/(9 xx 5^(n + 1) - 20 xx 5^n)`
Simplify the following:
`(3^(n + 4) xx 3^((n - 2)(n + 2)))/(3^(n(n + 1)) xx 9^(n + 1))`
Write `(x^-1 - y^-1)/(x^-2 - y^-2)` in the simplest form.
Simplify:
`((a^(x + y))^(x - y)(a^(y - z))^(y + z))/((a^(x + z))^(x - z))`
Find the value of x and y from the following:
2x · 3y = 144
Find the value of x and y from the following:
3x · 5y = 675
Find the values of x, y and z from the following:
2x · 3y · 5z = 24000
If a = bx, b = cy and c = az prove that xyz = 1.
Prove that `(a^x/a^y)^(x + y) (a^y/a^z)^(y + z) (a^z/a^x)^(z + x) = 1`.
Prove that `(x^a/x^b)^(a^2 + ab + b^2) (x^b/x^c)^(b^2 + bc + c^2) (x^c/x^a)^(c^2 + ca + a^2) = 1`.
Prove that:
`1/(1 + x^(b - a) + x^(c - a)) + 1/(1 + x^(a - b) + x^(c - b)) + 1/(1 + x^(b - c) + x^(a - c)) = 1`
Prove that `(x + y + z)/((xy)^-1 + (yz)^-1 + (zx)^-1) = xyz`.
If `x = a^(m + n), y = a^(n + l)` and `z = a^(l + m),` prove that `x^my^nz^l = x^ny^lz^m`
If `x = p^(m + n) * q^l, y = p^(n + l) * q^m, z = p^(l + m) * q^n` prove that `x^(m - l) * y^(n - l) * z^(l - m) = 1`.
If `a = x * y^(p - 1), b = x * y^(q - 1), c = x * y^(r - 1)`, prove that `a^(q - r) * b^(r - p) * c^(p - q) = 1`.
If 2x = 3y = 72z, find the relation between x, y and z.
If 3x = 5y = 225z, find the relation between x, y and z.
Nootan solutions for Mathematics [English] Class 9 ICSE 6 Indices/Exponents Exercise 6B [Page 131]
Evaluate the following:
`(243)^(1/5)`
Evaluate the following:
`(64)^(-3/2)`
Evaluate the following:
`(-32)^(2/5)`
Evaluate the following:
`(216)^(4/3)`
Evaluate the following:
`(25/9)^(3/2) + (27/64)^(-1/3)`
Evaluate the following:
`(81/256)^(1/4) xx (32/243)^((-2)/5)`
Evaluate the following:
`5^-1 xx 3^0 + 25^(1/2)`
Evaluate the following:
`3^-2 xx 2^0 - (27)^(-1/3)`
Evaluate the following:
`(27)^(4/3) - 5^0 xx (1/9)^(-3/2) + (81)^(1/2)`
Evaluate the following:
`(sqrt(3^4) xx root(3)(27))/(root(4)(81)) + (1/2)^-2`
Evaluate the following:
`(root(4)(2^8) xx root(5)(243) xx 5^0)/root(3)(216)`
If x = 2, y = 3, find xx + y–y.
If x = –2, y = –3, find xx + yy.
If x = 4, y = 3, find xy + yx.
If x = –1, y = 2, z = –3, find xy + yx + zx.
If x = 2, y = 3, z = 4, find xz + y–x + zy.
Nootan solutions for Mathematics [English] Class 9 ICSE 6 Indices/Exponents Exercise 6C [Page 133]
Solve the following equation:
`2^(3x - 2) = 1`
Solve the following equation:
`3^(5x - 1) = root(4)(3)`
Solve the following equation:
`5^(3x - 1) = root(3)(5)`
Solve the following equation:
`2^(4x + 1) = root(4)(256)`
Solve the following equation:
`2^(3x + 1) = 16 xx 2^(2x)`
Solve the following equation:
`2^(4x - 3) = 4 xx 2^(2x - 1)`
Solve the following equation:
22x – 5.2x + 4 = 0
Solve the following equation:
`3^(2x + 3) - 28.3^x + 1 = 0`
Solve the following equation:
`4^(x^2) : 4^x = 16 : 1`
Solve the following equation:
`3^(2x + 1) = 3^(2x - 1) + 216`
If `a^x * b^(3y) = root(4)(a^3 * b^-6)`, find the values of x and y, where a and b are different positive prime numbers.
Solve:
`sqrt((4/3)^(1 - 3x)) = 2 10/27`
Solve:
`sqrt((2/5)^(4x - 3)) = 15 5/8`
If `2^(3x) = (root(3)(32))^(4/y) = (sqrt(8))^5`, then find the values of x and y.
If `5^(2x - 1) = 5^(2x - 2) + 100`, find the value of (2x)3x.
If `3^(3x + 1) = 3^(3x - 1) + 72`, find the value of `(3x + 1)^(2x)`.
Solve for x and y:
`8^(3 - x/2) - 2^(2y) = 0` and `(sqrt(32))^x ÷ 2^y = 4`
Nootan solutions for Mathematics [English] Class 9 ICSE 6 Indices/Exponents Exercise 6D [Pages 133 - 134]
Multiple Choice Questions Choose the correct answer from the given four options in each of the following questions:
x0 is equal to ______.
0
1
x
None of these
a5 × a–5 is equal to ______.
0
1
a–10
a
`(x^4 xx x^3)/x^9` is equal to ______.
x2
x
`1/x`
`1/x^2`
If x = 3, y = 2, then the value of xx + yy is ______.
42
35
31
17
(81)0.18 × (81)0.07 is equal to ______.
9
3
27
81
If `2^(2x + 2) - 5 * 2^x + 1 = 0`, then the value of x is ______.
0
1
–1
2
If 2x · 3y = 288, then the value of y is ______.
1
2
–2
–1
If a = bx, b = cy, c = az, then the value of 8 xyz is ______.
1
2
4
8
`(a^x/(a^-y))^(x - y) (a^y/a^-z)^(y - z) (a^z/a^-x)^(z - x)` is equal to ______.
0
1
a
axyz
`(3^(n + 1) xx 9^(n - 1))/(3^n xx 9^(n + 1))` is equal to ______.
27
9
`1/9`
`1/27`
Valid Statements Questions In the following questions, two statements (i) and (ii) are given. Choose the valid statement.
(i) lf x = 2, y = 1 then xx + yy = 5.
(ii) If a = bx, b = cy, c = az then xyz = 1.
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
(i) lf m ≠ n and (m + n)–1 (m–1 + n–1) = mxny then x + y = 2.
(ii) If 2x = 3y = 108z then `2/y + 3/z = 1/x`
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
(i) `(a^x/a^y)^(x + y) * (a^y/a^z)^(y + z) * (a^z/a^x)^(z + x) = 1`
(ii) am × an = am – n
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
(i) `(64)^(-3//2) = 512`
(ii) `5^-1 xx 3^0 = 1/5`
Only (i)
Only (ii)
Both (i) and (ii)
Neither (i) nor (ii)
Solutions for 6: Indices/Exponents
![Nootan solutions for Mathematics [English] Class 9 ICSE chapter 6 - Indices/Exponents Nootan solutions for Mathematics [English] Class 9 ICSE chapter 6 - Indices/Exponents - Shaalaa.com](/images/mathematics-english-class-9-icse_6:f26eb985e8254aa987299226050d7c71.jpg)
Nootan solutions for Mathematics [English] Class 9 ICSE chapter 6 - Indices/Exponents
Shaalaa.com has the CISCE Mathematics Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Nootan solutions for Mathematics Mathematics [English] Class 9 ICSE CISCE 6 (Indices/Exponents) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Nootan textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Mathematics [English] Class 9 ICSE chapter 6 Indices/Exponents are .
Using Nootan Mathematics [English] Class 9 ICSE solutions Indices/Exponents exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Nootan Solutions are essential questions that can be asked in the final exam. Maximum CISCE Mathematics [English] Class 9 ICSE students prefer Nootan Textbook Solutions to score more in exams.
Get the free view of Chapter 6, Indices/Exponents Mathematics [English] Class 9 ICSE additional questions for Mathematics Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.
