Question

If x = 2, y = 3, z = 4, find x^z + y^–x + z^y.

Answer 1

Given:

x = 2

y = 3

z = 4

We need to find the value of:

x^z + y^–x + z^y

Step-wise calculation:

1. Calculate (x^z):

2⁴ = 16

2. Calculate (y^–x):

`3^-2 = 1/3^2`

`3^-2 = 1/9`

3. Calculate (z^y):

4³ = 64

4. Add the values:

`16 + 1/9 + 64 = 80 + 1/9`

`16 + 1/9 + 64 = 720/9 + 1/9`

`16 + 1/9 + 64 = 721/9`

So the result is `721/9`.