Question

If x = –1, y = 2, z = –3, find x^y + y^x + z^x.

Answer 1

Given:

x = –1

y = 2

z = –3

We need to find:

x^y + y^x + z^x

Step-wise calculation:

1. Calculate

x^y = (–1)²

x^y = 1

2. Calculate

y^x = 2^–1

`y^x = 1/2`

3. Calculate

z^x = (–3)^–1

`z^x = 1/(-3)`

`z^x = -1/3`

Now, add these values:

`1 + 1/2 - 1/3 = 6/6 + 3/6 - 2/6`

`1 + 1/2 - 1/3 = 7/6`