Question

Solve the following equation:

`2^(3x - 2) = 1`

Answer 1

Given: `2^(3x - 2) = 1`

Step-wise calculation:

1. Recall that any number raised to the power zero is 1, so:

`2^(3x - 2) = 1`

`2^(3x - 2) = 2^0`

2. Since the bases are the same (base 2), the exponents must be equal:

3x – 2 = 0

3. Solve for (x):

3x = 2

`x = 2/3`