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प्रश्न
Solve the following equation:
`2^(3x - 2) = 1`
योग
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उत्तर
Given: `2^(3x - 2) = 1`
Step-wise calculation:
1. Recall that any number raised to the power zero is 1, so:
`2^(3x - 2) = 1`
`2^(3x - 2) = 2^0`
2. Since the bases are the same (base 2), the exponents must be equal:
3x – 2 = 0
3. Solve for (x):
3x = 2
`x = 2/3`
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