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Evaluate the following: (81/256)^(1/4) × (32/243)^((−2)/5) - Mathematics

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Question

Evaluate the following:

`(81/256)^(1/4) xx (32/243)^((-2)/5)`

Evaluate
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Solution

Given expression: `(81/256)^(1/4) xx (32/243)^((-2)/5)`

Step-wise calculation:

1. Write the bases as powers of primes:

81 = 34

256 = 44 = (28)

32 = 25

243 = 35 

2. Simplify each power:

`(81/256)^(1/4) = (3^4/2^8)^(1/4)`

`(81/256)^(1/4) = (3^(4 xx 1/4))/(2^(8 xx 1/4))`

`(81/256)^(1/4) = 3^1/2^2`

`(81/256)^(1/4) = 3/4`

`(32/243)^(-2/5) = (2^5/3^5)^(-2/5)`

`(32/243)^(-2/5) = (2^(5 xx -2/5))/(3^(5 xx -2/5))`

`(32/243)^(-2/5) = 2^-2/3^-2`

`(32/243)^(-2/5) = 3^2/2^2`

`(32/243)^(-2/5) = 9/4`

3. Multiply the two simplified terms:

`3/4 xx 9/4 = 27/16`

So, the value of `(81/256)^(1/4) xx (32/243)^((-2)/5)` is `27/16`.

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Chapter 6: Indices/Exponents - Exercise 6B [Page 131]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 6 Indices/Exponents
Exercise 6B | Q 2. (ii) | Page 131
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