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Evaluate the following: (25/9)^(3/2) + (27/64)^(−1/3) - Mathematics

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Question

Evaluate the following:

`(25/9)^(3/2) + (27/64)^(-1/3)`

Evaluate
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Solution

Given: `(25/9)^(3/2) + (27/64)^(-1/3)`

Step-wise calculation:

1. Calculate `(25/9)^{3/2)`:

`(25/9)^(3/2) = ((25/9)^(1/2))^3`

`(25/9)^(3/2) = (sqrt(25)/sqrt(9))^3`

`(25/9)^(3/2) = (5/3)^3`

`(25/9)^(3/2) = 125/27`

2. Calculate`(27/64)^(-1/3)`:

`(27/64)^(-1/3) = (64/27)^(1/3)`

`(27/64)^(-1/3) = (root(3)(64))/(root(3)(27))`

`(27/64)^(-1/3) = 4/3`

3. Add the two results:

`125/27 + 4/3 = 125/27 + (4 xx 9)/(3 xx 9)`

`125/27 + 4/3 = 125/27 + 36/27`

`125/27 + 4/3 = (125 + 36)/27`

`125/27 + 4/3 = 161/27`

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Chapter 6: Indices/Exponents - Exercise 6B [Page 131]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 6 Indices/Exponents
Exercise 6B | Q 2. (i) | Page 131
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