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Solve the following equation: 2^(3x + 1) = 16 × 2^(2⁢x) - Mathematics

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Question

Solve the following equation:

`2^(3x + 1) = 16 xx 2^(2x)`

Sum
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Solution

Given equation: `2^(3x + 1) = 16 xx 2^(2x)`

Step-wise calculation:

1. Express 16 as a power of 2:

16 = 24 

So the equation becomes:

`2^(3x + 1) = 2^4 xx 2^(2x)`

2. Use the property of exponents:

`2^4 xx 2^(2x) = 2^(4 + 2x)`

Hence: `2^(3x + 1) = 2^(4 + 2x)`.

3. Since the bases are the same and nonzero, equate the exponents:

3x + 1 = 4 + 2x

4. Solve for (x):

3x + 1 = 4 + 2x

3x – 2x = 4 – 1

x = 3

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Chapter 6: Indices/Exponents - Exercise 6C [Page 133]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 6 Indices/Exponents
Exercise 6C | Q 2. (i) | Page 133
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