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Question
Evaluate the following:
2 log 2 + 4 log 3 + log 5 – log 7.5 – log 2.16
Evaluate
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Solution
Given: 2 log 2 + 4 log 3 + log 5 – log 7.5 – log 2.16
Step-wise calculation:
1. Use log rules:
a log x = log xa
log A + log B = log (AB)
`log A - log B = log (A/B)`
2. 2 log 2 + 4 log 3 + log 5 – log 7.5 – log 2.16
= log (22) + log (34) + log (5) – log (7.5) – log (2.16)
= log (4) + log (81) + log (5) – log (7.5) – log (2.16)
= `log (4 xx 81 xx 5)/(7.5 xx 2.16)`
3. Compute the product/quotient:
4 × 81 × 5 = 1620
7.5 × 2.16 = 16.2
So expression
= `log (1620/16.2)`
= log (100)
4. Assuming log = log10 common logarithm
log (100) = 2
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Is there an error in this question or solution?
Chapter 7: Logarithms - Exercise 7B [Page 146]
