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Question
Express the following in exponential form:
`log_4 1/32 = - 5/2`
Sum
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Solution
Given: `log_4 1/32 = - 5/2`
Step-wise calculation:
By definition of logarithm (logab = c ⇔ ac = b),
We rewrite: `4^(-5/2) = 1/32`
Then `4^(-5/2) = (4^(1/2))^(-5)`
`4^(-5/2) = (sqrt4)^(-5)`
`4^(-5/2) = 2^(-5)`
`4^(-5/2) = 1/32`
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