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Evaluation of Algebraic Expressions

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Topics

Estimated time: 9 minutes
  • Introduction
  • Example 1
  • Example 2
  • Example 3
  • Key Points Summary
CISCE: Class 6

Introduction

Evaluating algebraic expressions means finding the value of an expression by replacing each variable with a given number. .

CISCE: Class 6

Example 1

(i) 4m − 9 for m = −3

= 4 × (−3) − 9

= −12 − 9

= −21

(ii) 5p + 24 for p = −3

= 5 × (−3) + 24

= −15 + 24

= 9 

CISCE: Class 6

Example 2

If x = 2 and y = 3, evaluate:
Solution:

  1. xy = x × y = 2 × 3 = 6

  2. 5x²y = 5 × x × x × y = 5 × 2 × 2 × 3 = 60

  3. 5y² = 5 × y × y = 5 × 3 × 3 = 45

  4. (5y)² = 5y × 5y = 5 × 5 × y × y = 25 × 3 × 3 = 225
CISCE: Class 6

Example 3

If a = 3 and b = −4, evaluate 2a² − b².
Solution:

2a² − b² = (2 × a × a) − (b × b)

= (2 × 3 × 3) − (−4 × −4)

= 18 − (16)

= 18 − 16

= 2 

CISCE: Class 6

Key Points Summary

  • Always write down the substituted expression first.

  • Compute exponents before other operations.

  • Simplify one step at a time for clarity.

Common Errors

  • Forgetting negatives: −3 × 4 ≠ −3 + 4

  • Wrong order: Adding before multiplying.

  • Skipping steps: Leads to sign and calculation mistakes.

Test Yourself

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