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R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 5 - Arithmetic Progression [1990 edition]

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R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 5 - Arithmetic Progression - Shaalaa.com
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Solutions for Chapter 5: Arithmetic Progression

Below listed, you can find solutions for Chapter 5 of CBSE, Karnataka Board R.S. Aggarwal for Mathematics [English] Class 10.


EXERCISE 5AEXERCISE 5BEXERCISE 5CEXERCISE 5DMULTIPLE-CHOICE QUESTIONS (MCQ)
EXERCISE 5A [Pages 260 - 263]

R.S. Aggarwal solutions for Mathematics [English] Class 10 5 Arithmetic Progression EXERCISE 5A [Pages 260 - 263]

1. (i)Page 260

Show that the progression given below is an AP. Find the first term, common difference and next term.

9, 15, 21, 27, ....

1. (ii)Page 260

Show that the progression given below is an AP. Find the first term, common difference and next term.

11, 6, 1, –4, ....

1. (iii)Page 260

Show that the progression given below is an AP. Find the first term, common difference and next term.

`-1, (-5)/6, (-2)/3, (-1)/2`, .... 

1. (iv)Page 260

Show that the progression given below is an AP. Find the first term, common difference and next term.

`sqrt(2), sqrt(8), sqrt(18), sqrt(32)`,....

1. (v)Page 260

Show that the progression given below is an AP. Find the first term, common difference and next term.

`sqrt(20), sqrt(45), sqrt(80), sqrt(125)`,....

2. (i)Page 261

Find the 20th term of the AP 9, 13, 17, 21,....

2. (ii)Page 261

Find the 35th term of AP 20, 17, 14, 11,....

2. (iii)Page 261

Find the 18th term of the AP `sqrt(2), sqrt(18), sqrt(50), sqrt(98)`,....

2. (iv)Page 261

Find the 9th term of the AP `3/4, 5/4, 7/4, 9/4,`....

2. (v)Page 261

Find the 15th term of the AP –40, –15, 10, 35,....

3. (i)Page 261

Find the 37th term of the AP `6, 7 3/4, 9 1/2, 11 1/4,`....

3. (ii)Page 261

Find the 25th term of the AP `5, 4 1/2, 4, 3 1/2, 3,`....

4.Page 261

Find the value of p for which the numbers 2p – 1, 3p + 1, 11 are in AP. Hence, find the numbers.

5. (i)Page 261

Find the nth term of the following APs:

5, 11, 17, 23, ....

5. (ii)Page 261

Find the nth term of the following APs:

16, 9, 2, –5, ....

6.Page 261

If the nth term of a progression is (4n – 10) show that it is an AP. Find its (i) first term, (ii) common difference, and (iii) 16th term.

7.Page 261

How many terms are there in the AP 6, 10, 14, 18, ..., 174?

8.Page 261

How many terms are there in the AP 41, 38, 35, ...,8?

9.Page 261

Find the number of terms in the following A.P.

`18, 15 1/2, 13`, ..., – 47

10.Page 261

Which term of the AP 3, 8, 13, 18, ... is 88?

11.Page 261

Which term of AP 72, 68, 64, 60, ... is 0?

12.Page 261

Which term of the AP `5/6, 1, 1 1/6, 1 1/3,` ... is 3?

13.Page 261

Which term of the AP 21, 18, 15, ... is –81?

14.Page 261

Which term of the A.P. 8, 14, 20, 26, ... will be 72 more than its 41st term?

15.Page 261

Which term of the A.P. 5, 15, 25, ... will be 130 more than its 31st term?

16.Page 261

If the 10th term of an AP is 52 and 17th term is 20 more than its 13th  term, find the AP.

17.Page 261

Find the middle term of the AP 6, 13, 20, ..., 216.

18.Page 261

Find the middle term of the AP 10, 7, 4, ..., (–62).

19.Page 261

Find the sum of two middle most terms of the AP `-4/3, -1 (-2)/3, ..., 4 1/3.`

20.Page 261

Find the 8th term from the end of the AP 7, 10, 13, ..., 184.

21.Page 262

Find the 6th term form the end of the AP 17, 14, 11, ..., (–40).

22.Page 262

Is 184 a term of the AP 3, 7, 11, 15, ...?

23.Page 262

Is –150 a term of the AP 11, 8, 5, 2, ...?

24.Page 262

Which term of the A.P. 121, 117, 113, ... is its first negative term?

[Hint: Find n for an < 0]

25.Page 262

Which term of the A.P. `20, 19 1/4, 18 1/2, 17 3/4,` ... is the first negative term?

26.Page 262

The 7th term of an AP is –4 and its 13th term is –16. Find the AP.

27.Page 262

The 4th term of an AP is zero. Prove that its 25th term is triple its 11th term.

28.Page 262

If the sixth term of an AP is zero then show that its 33rd term is threе times its 15th term.

29.Page 262

The 4th term of an AP is 11. The sum of the 5th and 7th terms of this AP is 34. Find its common difference.

30.Page 262

The 9th term of an AP is –32 and the sum of its 11th and 13th terms is –94. Find the common difference of the AP. 

31.Page 262

Determine the nth term of the AP whose 7th term is –1 and 16th term is 17.

32.Page 262

If 4 times the 4th term of an A.P. is equal to 18 times its 18th term, then find its 22nd term.

33.Page 262

If 10 times the 10th term of an AP is equal to 15 times the 15th term, show that its 25th term is zero.

34.Page 262

Find the common difference of an AP whose first term is 5 and the sum of its first four terms is half the sum of the next four terms.

35.Page 262

The sum of the 2nd term and the 7th term of an A.P. is 30. If its 15th term is 1 less than twice its 8th term, find the A.P.

36.Page 262

For what value of n, the nth terms of the arithmetic progressions 63, 65, 67, ... and 3, 10, 17, ... equal?

37.Page 262

The 17th term of AP is 5 more than twice its 8th term. If the 11th term of the AP is 43, find its nth term.

38.Page 262

The 24th term of an AP is twice its 10th term. Show that its 72nd term is 4 times its 15th term.

39.Page 262

The 19th term of an AP is equal to 3 times its 6th term. If its 9th term is 19, find the AP.

40.Page 262

If the pth term of an AP is q and its qth term is p then show that its (p + q)th term is zero.

41.Page 263

The first and last terms of an AP are a and l respectively. Show that the sum of the nth term from the beginning and the nth term form the end is (a + l).

42.Page 263

How many two-digit numbers are divisible by 6?

43.Page 263

How many two-digits numbers are divisible by 3?

44.Page 263

How many three-digit numbers are divisible by 9?

45.Page 263

How many numbers are there between 101 and 999, which are divisible by both 2 and 5?

46.Page 263

In a flower bed, there are 43 rose plants in the first row, 41 in the second, 39 in the third, and so on. There are 11 rose plants in the last row. How many rows are there in the flower bed?

47.Page 263

A sum of ₹ 2800 is to be used to award four prizes. If each prize after the first is ₹ 200 less than the preceding prize, find the value of each of the prizes.

48.Page 263

Find how many integers between 200 and 500 are divisible by 8.

EXERCISE 5B [Pages 267 - 268]

R.S. Aggarwal solutions for Mathematics [English] Class 10 5 Arithmetic Progression EXERCISE 5B [Pages 267 - 268]

1.Page 267

Determine k so that (3k – 2), (4k – 6) and (k + 2) are three consecutive terms of an AP.

2.Page 267

Find the value of x for which the numbers (5x + 2), (4x – 1) and (x + 2) are in AP.

3.Page 267

If (3y – 1), (3y + 5) and (5y + 1) are three consecutive terms of an AP then find the value of y.

4.Page 267

Find the value of x for which (x + 2), 2x, (2x + 3) are three consecutive terms of an AP.

5.Page 267

Show that (a – b)2, (a2 + b2) and (a2 + b2) are in AP.

6.Page 267

Find three numbers in AP whose sum is 15 and whose product is 105.

HINT: Let the numbers be (a – d), a, (a + d).

7.Page 267

The sum of three numbers in AP is 3 and their product is –35. Find the numbers.

8.Page 267

Divide 24 in three parts such that they are in AP and their product is 440.

9.Page 267

The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. Find these terms.

10.Page 268

The angles of a quadrilateral are in AP whose common difference is 10°. Find the angles.

11.Page 268

Find four numbers in AP whose sum is 28 and the sum of whose squares is 216.

12.Page 268

Divide 32 into four parts which are the four terms of an AP such that the product of the first and the fourth terms is to the product of the second and the third terms as 7 : 15.

HINT: Let these parts be (a – 3d), (a – d), (a + d) and (a + 3d).

13.Page 268

The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.

HINT: Let these terms be (a – d), a, (a + d).

14.Page 268

The sum of three numbers in AP is 18. If the product of first and third number is five times the common difference, find the numbers.

HINT: Let these numbers be (a – d), a and (a + d).

15.Page 268

If the numbers a, 7, b, 23, c are in AP, find a, b and c.

EXERCISE 5C [Pages 285 - 288]

R.S. Aggarwal solutions for Mathematics [English] Class 10 5 Arithmetic Progression EXERCISE 5C [Pages 285 - 288]

1. (i)Page 285

Find the sum of the following APs:

2, 7, 12, 17, ... to 19 terms.

1. (ii)Page 285

Find the sum of the following APs:

9, 7, 5, 3, ... to 14 terms.

1. (iii)Page 285

Find the sum of the following APs:

–37, –33, –29, ... to 12 terms.

1. (iv)Page 285

Find the sum of the following APs:

`1/15, 1/12, 1/10`, ... to 11 terms.

1. (v)Page 285

Find the sum of the following APs:

0.6, 1.7, 2.8, ... to 100 terms. 

2. (i)Page 285

Find the sum of  the following arithmetic series:

`7 + 10 1/2 + 14 + ... + 84`

2. (ii)Page 285

Find the sum of the following arithmetic series:

34 + 32 + 30 + ... + 10

2. (iii)Page 285

Find the sum of the following arithmetic series:

(–5) + (–8) + (–11) + ... + (–230)

2. (iv)Page 285

Find the sum of the following arithmetic series:

5 + (–41) + 9 + (–39) + 13 + (–37) + 17 + ... + (–5) + 81 + (–3)

HINT: Given sum = (5 + 9 + 13 + 17 + ... + 81) + {(–41) + (–39) + ... + (–3)}.

3.Page 285

Find the sum of first n terms of an AP whose nth term is (5 – 6n). Hence, find the sum of its first 20 terms.

4.Page 285

The sum of the first n terms of an AP is (3n2 + 6n). Find the nth term and the 15th term of this AP.

5.Page 285

The sum of the first n terms of an AP is given by Sn = (3n2 – 4n). Find its

  1. nth term,
  2. first term and
  3. common difference.
6. (i)Page 285

The sum of the first n terms of an AP is `((5n^2)/2 + (3n)/2)`. Find the nth term and the 20th term of this AP.

6. (ii)Page 285

The sum of the first n terms of an AP is `((3n^2)/2 + (5n)/2)`. Find its nth term and the 25th term.

7.Page 285

If mth term of an AP is `1/n` and nth term is `1/m` then find the sum of its first mn terms.

8.Page 285

How many terms of the A.P. 21, 18, 15, ... must be added to get the sum 0?

9.Page 285

How many terms of the AP. 9, 17, 25 … must be taken to give a sum of 636?

10.Page 285

How many terms of the AP 63, 60, 57, 54, ... must be taken so that their sum is 693? Explain the double answer.

11.Page 285

How many terms of the AP `20, 19 1/3 , 18 2/3, ...` must be taken so that their sum is 300? Explain the double answer.

12.Page 285

Find the sum of the odd numbers between 0 and 50.

13.Page 286

Find the sum of all natural numbers between 200 and 400 which are divisible by 7.

14.Page 286

Find the sum of first 40 positive integers divisible by 6.

15.Page 286

Find the sum of first 15 multiples of 8.

16.Page 286

Find the sum of all multiples of 9 lying between 300 and 700.

17.Page 286

Find the sum of all three-digits natural numbers which are divisible by 13.

18.Page 286

Find the sum of first 100 even natural numbers which are divisible by 5.

 

19.Page 286

Find the sum of n terms of the following series:

`(4 - 1/n) + (4 - 2/n) + (4 - 3/n) +` ....

20.Page 286

In an AP, It is given that S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms.

21.Page 286

In an AP, the first term is 2, the last term is 29 and the sum of all the terms is 155. Find the common difference.

22.Page 286

In an AP, the first term is –4, the last term is 29 and the sum of all its terms is 150. Find its common difference.

23.Page 286

The first and last terms of an AP are 17 and 350, respectively. If the common difference is 9, how many terms are there, and what is their sum?

24.Page 286

The first term of an A.P. is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

25.Page 286

In an AP, the first term is 22, nth terms is –11 and sum of first n terms is 66. Find n and hence find the common difference.

26.Page 286

The 12th term of an AP is –13 and the sum of its first four terms is 24. Find the sum of its first 10 terms.

27.Page 286

The sum of the first 7 terms of an AP is 182. If its 4th and 17th terms are in the ratio 1 : 5, find the AP.

28.Page 286

The sum of the first 9 terms of an AP is 81 and that of its first 20 terms is 400. Find the first term and the common difference of the AP.

29.Page 286

If the sum of first 7 terms of an A.P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A.P.

30.Page 286

Two APs have the same common difference. If the first terms of these APs be 3 and 8 respectively, find the difference between the sums of their first 50 terms.

31.Page 287

The sum first 10 terms of an AP is –150 and the sum of its next 10 terms is –550. Find the AP.

32.Page 287

The 13th term of an AP is 4 times its 3rd term. If its 5th term is 16, find the sum of its first 10 terms.

33.Page 287

The 16th term of an AP is 5 times its 3rd term. If its 10th term is 41, find the sum of its first 15 terms.

34. (i)Page 287

An AP 5, 12, 19, ... has 50 terms. Find its last term. Hence, find the sum of its last 15 terms.

34. (ii)Page 287

An AP 8, 10, 12, ... has 60 terms. Find its last term. Hence, find the sum of its last 10 terms.

35.Page 287

The sum of first n terms of two APs are in the ratio (3n + 8) : (7n + 15). Find the ratio of their 12th terms.

36.Page 287

The sum of the 4th and the 8th terms of an AP is 24 and the sum of its 6th and 10th terms is 44. Find the sum of its first 10 terms. 

37.Page 287

The sum of first m terms of an AP is (4m2 – m). If its nth term is 107, find the value of n. Also, find the 21st term of this AP.

38.Page 287

The sum of first q terms of an AP is (63q – 3q2). If its pth term is –60, find the value of p. Also, find the 11th term of its AP.

39.Page 287

Find the number of terms of the AP –12, –9, –6, ..., 21. If 1 is added to each term of this AP then find the sum of all terms of the AP thus obtained.

40.Page 287

Sum of the first 14 terms of an AP is 1505 and its first term is 10. Find its 25th term.

41.Page 287

Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

42.Page 287

In a school, students decided to plant trees in and around the school to reduce air pollution. It was decided that the number of trees that each section of each class will plant will be double of the class in which they are studying. If there are 1 to 12 classes in the school and each class has two section, find how many trees were planted by student. Which value is shown in the question?

43.Page 287

In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato and other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.

A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?

[Hint: to pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 × (5 + 3)]

44.Page 288

There are 25 trees at equal distance of 5 m in a line with a water tank, the distance of the water tank from the nearest tree being 10 m. A gardener waters all the trees separately, starting from the water tank and returning back to the water tank after watering each tree to get water for the next. Find the total distance covered by the gardener in order to water all the trees.

45.Page 288

A sum of Rs 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is Rs 20 less than its preceding prize, find the value of each of the prizes.

46.Page 288

A man saved ₹ 33000 in 10 months. In each month after the first, he saved ₹ 100 more than he did in the preceding month. How much did he save in the first month?

47.Page 288

A man arranges to pay off a debt of ₹ 36000 by 40 monthly instalments which form an arithmetic series. When 30 of the instalments are paid, he dies leaving one-third of the debt unpaid. Find the value of the first instalment.

48.Page 288

A contract on a construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day, etc., the penalty for each succeeding day being Rs. 50 more than for the preceding day. How much money does the contractor have to pay as a penalty if he has delayed the work by 30 days?

EXERCISE 5D [Pages 293 - 294]

R.S. Aggarwal solutions for Mathematics [English] Class 10 5 Arithmetic Progression EXERCISE 5D [Pages 293 - 294]

Very-Short and Short-Answer Questions

1.Page 293

The first three terms of an AP are respectively (3y – 1), (3y + 5) and (5y + 1), find the value of y .

2.Page 293

If k, (2k - 1) and (2k + 1) are the three successive terms of an AP, find the value of k.

3.Page 293

If 18, a, (b – 3) are in AP, then find the value of (2a – b).

4.Page 293

If the numbers a, 9, b, 25 from an AP, find a and b.

5.Page 293

If the numbers (2n – 1), (3n + 2) and (6n – 1) are in AP, find the value of n and the numbers.

6.Page 293

How many three-digit numbers are divisible by 7?

7.Page 293

How many three-digit natural numbers are divisible by 9?

8.Page 293

If the sum of first m terms of an AP is (2m2 + 3m) then what is its second term?

9.Page 293

What is the sum of first n terms of the AP a, 3a, 5a, ....

10.Page 293

What is the 5th term form the end of the AP 2, 7, 12, ..., 47?

11.Page 293

If an denotes the nth term of the AP 2, 7, 12, 17, ..., find the value of (a30 - a20).

12.Page 293

The nth term of an AP is (3n + 5). Find its common difference.

13.Page 293

The nth term of an AP is (7 – 4n). Find its common difference.

14.Page 293

Write the next term of the AP `sqrt(8), sqrt(18), sqrt(32),`....

15.Page 293

Write the next term of the AP `sqrt(2), sqrt(8), sqrt(18),`....

16.Page 293

Which term of the AP 21, 18, 15, ... is zero?

17.Page 293

Find the sum of the first n natural numbers.

18.Page 293

Find the sum of first n even natural numbers.

19.Page 293

The first term of an AP is p and its common difference is q. Find its 10th term.

20.Page 293

If `4/5`, a, 2 are in AP, find the value of a.

21.Page 293

If (2p + 1), 13, (5p - 3) are in AP, find the value of p.

22.Page 293

If (2p – 1), 7, 3p are in AP, find the value of p.

23.Page 293

If the sum of first p terms of an AP is (ap2 + bp), find its common difference.

24.Page 294

If the sum of first n terms is (3n+ 5n), find its common difference.

25.Page 294

Find an AP whose 4th term is 9 and the sum of its 6th and 13th terms is 40.

26.Page 294

What is the common difference of an AP in which a27 – a7 = 84?

27.Page 294

If 1 + 4 + 7 + 10 + ... + x = 287, find the value of x.

MULTIPLE-CHOICE QUESTIONS (MCQ) [Pages 296 - 298]

R.S. Aggarwal solutions for Mathematics [English] Class 10 5 Arithmetic Progression MULTIPLE-CHOICE QUESTIONS (MCQ) [Pages 296 - 298]

Choose the correct answer in each of the following questions:

1.Page 296

The common difference of the AР `1/p, (1 - p)/p, (1 - 2p)/p,` ... is ______.

  • p

  • –p

  • –1

  • 1

2.Page 296

The common difference of the A.P. \[\frac{1}{3}, \frac{1 - 3b}{3}, \frac{1 - 6b}{3}, ...\] is ______.

  • \[\frac{1}{3}\]
  • \[\frac{-1}{3}\]
  • b

  • –b

3.Page 296

The next term of the A.P. \[\sqrt{7}, \sqrt{28}, \sqrt{63}\] is ______.

  • \[\sqrt{70}\]
  • \[\sqrt{84}\]

  • \[\sqrt{97}\]
  • \[\sqrt{112}\]
4.Page 296

If 4, x1, x2, x3, 28 are in AP then x3 = ?

  • 19

  • 23

  • 22

  • Cannot be determined

5.Page 296

If the nth term of an AP is (2n + 1), then the sum of its first three terms is ______.

  • 6n + 3

  • 15

  • 12

  • 21

6.Page 296

The sum of first n terms of an AP is (3n2 + 6n). The common difference of the AP is ______.

  • 6

  • 9

  • 15

  • –3

7.Page 296

The sum of first n terms of an AP is (5n – n2). The nth term of the AP is ______.

  • (5 – 2n)

  • (6 – 2n)

  • (2n – 5)

  • (2n – 6)

8.Page 296

The sum of first n terms of an AP is (4n2 + 2n). The nth term of this AP is ______.

  • (6n – 2)

  • (7n – 3)

  • (8n – 2)

  • (8n + 2)

9.Page 296

The 7th term of an AP is –1 and its 16th term is 17. The nth term of the AP is ______.

  • (3n + 8)

  • (4n – 7)

  • (15 – 2n)

  • (2n – 15)

10.Page 296

The 5th term of an AP is –3 and its common difference is –4. The sum of its first 10 terms is ______.

  • 50

  • –50

  • 30

  • –30

11.Page 296

The 5th term of an AP is 20 and the sum of its 7th and 11th terms is 64. The common difference of the AP is ______.

  • 4

  • 5

  • 3

  • 2

12.Page 296

The 13th term of an AP is 4 times its 3rd term. If its 5th term is 16 then the sum of its first ten terms is ______.

  • 150

  • 175

  • 160

  • 135

13.Page 297

An AP 5, 12, 19, ... has 50 terms. Its last term is ______.

  • 343

  • 353

  • 348

  • 362

14.Page 297

The sum of first 20 odd natural numbers is ______.

  • 100

  • 210

  • 400

  • 420

15.Page 297

The sum of first 40 positive integers divisible by 6 is ______.

  • 2460

  • 3640

  • 4920

  • 4860

16.Page 297

How many two-digit numbers are divisible by 3?

  • 25

  • 30

  • 32

  • 36

17.Page 297

How many three-digit numbers are divisible by 9?

  • 86

  • 90

  • 96

  • 100

18.Page 297

What is the common difference of an AP in which a18 – a14 = 32?

  • 8

  • – 8

  • 4

  • – 4

19.Page 297

If an denotes the nth term of the AP 3, 8, 13, 18, ... then what is the value of (a30 – a20)?

  • 40

  • 36

  • 50

  • 56

20.Page 297

Which term of the AP 72, 63, 54, ... is 0?

  • 8th

  • 9th

  • 10th

  • 11th

21.Page 297

Which term of the AP 25, 20, 15, ... is the first negative term?

  • 10th

  • 9th

  • 8th

  • 7th

22.Page 297

Which term of the AP: 21, 42, 63, 84, ... is 210?

  • 9th

  • 10th

  • 11th

  • 12th

23.Page 297

What is 20th term from the end of the AP 3, 8, 13, ..., 253?

  • 163

  • 158

  • 153

  • 148

24.Page 297

(5 + 13 + 21 + ... + 181) = ?

  • 2476

  • 2337

  • 2219

  • 2139

25.Page 297

The sum of first 16 terms of the AP: 10, 6, 2, ... is ______.

 

  • 320

  • –320

  • –352

  • –400

26.Page 297

How many terms of the AP 3, 7, 11, 15, ... will make the sum 406?

  • 10

  • 12

  • 14

  • 20

27.Page 297

The 2nd term of an AP is 13 and its 5th term is 25. What is its 17th term?

  • 69

  • 73

  • 77

  • 81

28.Page 297

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is ______.

  • 3

  • 2

  • –3

  • –2

29.Page 298

The 8th term of an AP is 17 and its 14th term is 29. The common difference of the AP is ______.

  • 3

  • 2

  • 5

  • –2

30.Page 298

The 7th term of an AP is 4 and its common difference is –4. What is its first term?

  • 16

  • 20

  • 24

  • 28

31.Page 298

The number of terms in the AP 5, 9, 13, 17, ..., 185 is ______.

  • 31

  • 41

  • 51

  • 46

32.Page 298

If (2p + 1), 10 and (5p + 5) are three consecutive terms of an AP, then p = ?

  • –1

  • –2

  • 1

  • 2

Solutions for 5: Arithmetic Progression

EXERCISE 5AEXERCISE 5BEXERCISE 5CEXERCISE 5DMULTIPLE-CHOICE QUESTIONS (MCQ)
R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 5 - Arithmetic Progression - Shaalaa.com

R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 5 - Arithmetic Progression

Shaalaa.com has the CBSE, Karnataka Board Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board 5 (Arithmetic Progression) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Mathematics [English] Class 10 chapter 5 Arithmetic Progression are .

Using R.S. Aggarwal Mathematics [English] Class 10 solutions Arithmetic Progression exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in R.S. Aggarwal Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board Mathematics [English] Class 10 students prefer R.S. Aggarwal Textbook Solutions to score more in exams.

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