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Question
Which term of the AP `5/6, 1, 1 1/6, 1 1/3,` ... is 3?
Sum
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Solution
In the given AP, first term = `5/6` and common difference, d = `(1 - 5/6 = 1/6)`
Let its nth term be 3.
Now, Tn = 3
⇒ a + (n – 1) d = 3
⇒ `5/6 + (n - 1) xx 1/6 = 3`
⇒ `2/3 + n/6 = 3`
⇒ `n/6 = 7/3`
⇒ n = 14
Hence, the 14th term of the given AP is 3.
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