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Which term of the AP 5/6, 1, 1 1/6, 1 1/3, ... is 3?

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Question

Which term of the AP `5/6, 1, 1 1/6, 1 1/3,` ... is 3?

Sum
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Solution

In the given AP, first term = `5/6` and common difference, d = `(1 - 5/6 = 1/6)`
Let its nth term be 3.

Now, Tn = 3 

⇒ a + (n – 1) d = 3 

⇒ `5/6 + (n - 1) xx 1/6 = 3`

⇒ `2/3 + n/6 = 3`

⇒ `n/6 = 7/3`

⇒ n = 14 

Hence, the 14th term of the given AP is 3.

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Chapter 5: Arithmetic Progression - EXERCISE 5A [Page 261]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 5 Arithmetic Progression
EXERCISE 5A | Q 12. | Page 261
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