Question

Find the value of x for which the numbers (5x + 2), (4x – 1) and (x + 2) are in AP.

Answer 1

It is given that (5x + 2), (4x – 1) and (x + 2) are in AP.

∴ (4x – 1) – (5x + 2) = (x + 2) – (4x – 1)

⇒ 4x – 1 – 5x – 2 = x + 2 – 4x + 1

⇒ –x – 3 = –3x + 3

⇒ 3x – x = 3 + 3

⇒ 2x = 6

⇒ x = 3

Hence, the value of x is 3.