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Question
The common difference of the A.P. \[\frac{1}{3}, \frac{1 - 3b}{3}, \frac{1 - 6b}{3}, ...\] is ______.
Options
- \[\frac{1}{3}\]
- \[\frac{-1}{3}\]
b
–b
MCQ
Fill in the Blanks
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Solution
The common difference of the A.P. \[\frac{1}{3}, \frac{1 - 3b}{3}, \frac{1 - 6b}{3}, ...\] is –b.
Explanation:
Let a be the first term and d be the common difference.
The given A.P. is \[\frac{1}{3}, \frac{1 - 3b}{3}, \frac{1 - 6b}{3}, . . .\]
Common difference = d = Second term – First term
= \[\frac{1 - 3b}{3} - \frac{1}{3}\]
= \[\frac{- 3b}{3} = - b\]
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