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Obtain the Sum of the First 56 Terms of an A.P. Whose 18th And 39th Terms Are 52 and 148 Respectively. - Algebra Mathematics 1

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Question

Obtain the sum of the first 56 terms of an A.P. whose 18th and 39th terms are 52 and 148 respectively.

Sum
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Solution

t18 = 52 and t39 = 148 S56 = ? 

tn = a + (n-1)d

t18 = a +( 18 - 1) d 

52 = a + 17 d     ......(i) 

t39 = a + (39 -1) d

∴ 148 = a + 38d   ........(2) 

Adding (1) and (2) 

a + 17d = 52

a + 38d = 148 

2a = 55d = 200 .......(3)

Sn = `n/2` [2a + (n - 1) d ]

S56 = `56/2` [2a + (56 -1) d] 

      = 28 [2a + 55d ]

      = 28(200) [from eq (3)]

S56  = 5600 

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2014-2015 (July)

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