Advertisements
Advertisements
Question
How many multiples of 4 lie between 10 and 250?
Advertisements
Solution
Numbers between 10 and 250 which are multiple of 4 are as follows:
12, 16, 20, 24, ........., 248
Clearly this forms an A.P. with first term a = 12,
Common difference d = 4 and last term I = 248
⇒ 248 = 12 + (n – 1)(4)
⇒ 248 = 12 + 4n – 4
⇒ 248 = 4n + 8
⇒ 4n = 248 – 8
⇒ 4n = 240
⇒ n = `240/4`
⇒ n = 60
Thus, 60 multiples of 4 lie between 10 and 250.
APPEARS IN
RELATED QUESTIONS
Divide 32 into four parts which are in A.P. such that the product of extremes is to the product of means is 7 : 15.
Show that a1, a2,..., an... form an AP where an is defined as below:
an = 3 + 4n
Also, find the sum of the first 15 terms.
If the sum of first m terms of an A.P. is the same as the sum of its first n terms, show that the sum of its first (m + n) terms is zero
If `4/5`, a, 2 are in AP, find the value of a.
The next term of the A.P. \[\sqrt{7}, \sqrt{28}, \sqrt{63}\] is ______.
Show that a1, a2, a3, … form an A.P. where an is defined as an = 3 + 4n. Also find the sum of first 15 terms.
A merchant borrows ₹ 1000 and agrees to repay its interest ₹ 140 with principal in 12 monthly instalments. Each instalment being less than the preceding one by ₹ 10. Find the amount of the first instalment.
How many terms of the AP: –15, –13, –11,... are needed to make the sum –55? Explain the reason for double answer.
The sum of n terms of an A.P. is 3n2. The second term of this A.P. is ______.
The nth term of an Arithmetic Progression is given by which expression?
