Advertisements
Advertisements
प्रश्न
How many multiples of 4 lie between 10 and 250?
Advertisements
उत्तर
Numbers between 10 and 250 which are multiple of 4 are as follows:
12, 16, 20, 24, ........., 248
Clearly this forms an A.P. with first term a = 12,
Common difference d = 4 and last term I = 248
⇒ 248 = 12 + (n – 1)(4)
⇒ 248 = 12 + 4n – 4
⇒ 248 = 4n + 8
⇒ 4n = 248 – 8
⇒ 4n = 240
⇒ n = `240/4`
⇒ n = 60
Thus, 60 multiples of 4 lie between 10 and 250.
APPEARS IN
संबंधित प्रश्न
If the pth term of an A. P. is `1/q` and qth term is `1/p`, prove that the sum of first pq terms of the A. P. is `((pq+1)/2)`.
Find the sum of the first 25 terms of an A.P. whose nth term is given by an = 7 − 3n
Find the value of x for which the numbers (5x + 2), (4x – 1) and (x + 2) are in AP.
The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.
HINT: Let these terms be (a – d), a, (a + d).
Write an A.P. whose first term is a and common difference is d in the following.
a = –19, d = –4
Sum of 1 to n natural numbers is 36, then find the value of n.
In an A.P., the first term is 22, nth term is −11 and the sum to first n terms is 66. Find n and d, the common difference
The sum of first 9 terms of an A.P. is 162. The ratio of its 6th term to its 13th term is 1 : 2. Find the first and 15th term of the A.P.
The common difference of the A.P. is \[\frac{1}{2q}, \frac{1 - 2q}{2q}, \frac{1 - 4q}{2q}, . . .\] is
Which term of the AP 3, 15, 27, 39, ...... will be 120 more than its 21st term?
