Question

The common difference of the A.P. is \[\frac{1}{2q}, \frac{1 - 2q}{2q}, \frac{1 - 4q}{2q}, . . .\] is 

 

Options

• −1

• 1

• q

• 2q

Answer 1

Let a be the first term and d be the common difference.
The given A.P. is  \[\frac{1}{2q}, \frac{1 - 2q}{2q}, \frac{1 - 4q}{2q}, . . .\]

Common difference = d = Second term − First term
                                       = \[\frac{1 - 2q}{2q} - \frac{1}{2q}\]

                                       = \[\frac{- 2q}{2q} = - 1\]