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Question
The common difference of the A.P. is \[\frac{1}{2q}, \frac{1 - 2q}{2q}, \frac{1 - 4q}{2q}, . . .\] is
Options
−1
1
q
2q
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Solution
Let a be the first term and d be the common difference.
The given A.P. is \[\frac{1}{2q}, \frac{1 - 2q}{2q}, \frac{1 - 4q}{2q}, . . .\]
Common difference = d = Second term − First term
= \[\frac{1 - 2q}{2q} - \frac{1}{2q}\]
= \[\frac{- 2q}{2q} = - 1\]
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