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Determine K So that (3k -2), (4k – 6) and (K +2) Are Three Consecutive Terms of an Ap. - Mathematics

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Question

Determine k so that (3k -2), (4k – 6) and (k +2) are three consecutive terms of an AP.

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Solution

It is given that (3k -2) ,(4k -6) and (k +2) are three consecutive terms of an AP.

∴ (4k - 6) - (3k - 2) = (k+2) - (4k - 6)

⇒ 4k - 6 - 3k + 2 = k+2 - 4k +6

⇒  k - 4 = -3k + 8
⇒ k+ 3k = 8+4 

⇒  4k = 12 

⇒  k = 3 
Hence, the value of k is 3.

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Chapter 11: Arithmetic Progression - Exercises 2

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 11 Arithmetic Progression
Exercises 2 | Q 1

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