Question

Find the value of x for which the numbers (5x + 2), (4x - 1) and (x + 2) are in AP.

Answer 1

It is given that (5x + 2),(4x -1) and  (x+2) are in AP.

∴ (4x -1)- (5x +2) = (x+2) - (4x-1)

⇒ 4x -1 - 5x -2 = x+2 -4x +1

⇒ -x -3 = -3x+3

⇒ 3x -x=3+3

⇒2x=6

⇒ x =3

Hence, the value of x is 3.