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Find the sum of the following APs: 2, 7, 12, ..., to 10 terms.

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Question

Find the sum of the following APs:

2, 7, 12, ..., to 10 terms.

Sum
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Solution

2, 7, 12, …, to 10 terms

For this A.P.,

a = 2

d = a2 − a1

d = 7 − 2

d = 5

n = 10

We know that,

Sn = `n/2 [2a + (n - 1) d]`

S10 = `10/2 [2(2) + (10 - 1) × 5]`

= 5[4 + (9) × (5)]

= 5 × 49

= 245

Thus, the sum of first 10 terms is 245.

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Chapter 5: Arithmetic Progressions - EXERCISE 5.3 [Page 68]

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NCERT Mathematics [English] Class 10
Chapter 5 Arithmetic Progressions
EXERCISE 5.3 | Q 1. (i) | Page 68
ML Aggarwal Understanding Mathematics [English] Class 10 ICSE
Chapter 9 Arithmetic and Geometric Progressions
Exercise 9.3 | Q 1.1

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