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Question
The first and the last terms of an AP are 8 and 65 respectively. If the sum of all its terms is 730, find its common difference.
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Solution
Let a be the first term, d be the common difference and Tn be the last of the AP.
Given:
a = 8
Tn = 65
Sn = 730
We know:
Tn = a + (n − 1)d
⇒ 65 = 8 + (n − 1)d
⇒ 57 = (n − 1)d ...(i)
and `Sn=n/2(a+Tn)`
`730=n/2(8+65)`
`n/2=730/73`
n=2x10=20
On substituting n = 20 in (i), we get:
57 = (20 − 1)d
⇒ 57 = (19)d
⇒ d = 57/19=3
Thus, the common difference is 3.
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