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Find the sum of all the 11 terms of an A.P. whose middle most term is 30. - Mathematics

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Question

Find the sum of all the 11 terms of an A.P. whose middle most term is 30.

Sum
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Solution

Since, the total number of terms (n) = 11  ...[odd]

∴ Middle most term = `(n + 1)^("th")/2` term

= `((11 + 1)/2)^("th")` term

= 6th term

Given that,

a6 = 30  ...[∵ an = a + (n − 1)d]

⇒ a + (6 − 1)d = 30    

⇒ a + 5d = 30    ...(i)

∵ Sum of n terms of an AP,

Sn = `n/2[2a + (n - 1)d]`

∴ S11 = `11/2[2a + (11 - 1)d]`

= `11/2(2a + 10d)`

= 11(a + 5d)

= 11 × 30   ...[From equation (i)]

= 330  

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Chapter 5: Arithematic Progressions - Exercise 5.3 [Page 54]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 5 Arithematic Progressions
Exercise 5.3 | Q 29 | Page 54

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