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Maharashtra State BoardSSC (English Medium) 10th Standard

If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term?

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Question

If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term?

Sum
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Solution

It is given that,

t9 = 0 

Now,

tn = a + (n - 1)d

t9 = a + (9 - 1)d

⇒ 0 = a + 8d

⇒ a = -8d      ...(1)

t29 = a + (29 - 1)d

= -8d + 28d           

= 20d      ...(2)

t19 = a + (19 - 1)d

= -8d + 18d

= 10d       ...(3)

From (2) and (3), we get

t29 = 2t19

Hence, the 29th term is twice the 19th term.

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Chapter 3: Arithmetic Progression - Practice Set 3.3 [Page 73]

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Balbharati Algebra Mathematics 1 [English] Standard 10 Maharashtra State Board
Chapter 3 Arithmetic Progression
Practice Set 3.3 | Q 9 | Page 73

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