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Question
Find the value of x for which (x + 2), 2x, ()2x + 3) are three consecutive terms of an AP.
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Solution
Since (x + 2), 2x and (2x +3) are in AP, we have
2x - (x+2) = (2x+3) -2x
⇒ x-2 = 3
⇒ x = 5
∴ x = 5
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