Question

If 4, x₁, x₂, x₃, 28 are in AP then x₃ = ?

Options

• 19

• 23

• 22

• Cannot be determined

Answer 1

22

Explanation:

Given AP is 4, x₁, x₂, x₃, 28. 

Clearly, a = 4 and T₅ = 28.

Now, T₅ = 28

⇒ a + 4d = 28

⇒ 4 + 4d = 28 

⇒ 4d = 24

⇒ d = 6

∴ x₃ = T₄

= (a + 3d) 

= (4 + 3 × 6) 

= 22